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Exercise: Special Functions (Modulus,... · Q22

Q.If f(x)=∣x−2∣+∣x+2∣f(x) = |x - 2| + |x + 2|, find f(−3)f(-3), f(0)f(0) and f(3)f(3).

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Step 1: At x=−3x=-3: ∣x−2∣=∣−5∣=5|x-2|=|-5|=5, ∣x+2∣=∣−1∣=1|x+2|=|-1|=1; f(−3)=5+1=6f(-3)=5+1=6.

Step 2: At x=0x=0: ∣x−2∣=∣−2∣=2|x-2|=|-2|=2, ∣x+2∣=∣2∣=2|x+2|=|2|=2; f(0)=2+2=4f(0)=2+2=4. …

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