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Example · Example 5

Q.A block of mass 10 kg10\ \text{kg} rests on a rough horizontal floor for which the coefficient of static friction is 0.40.4. Find the maximum static friction force available, and determine whether a horizontal push of 30 N30\ \text{N} is enough to set the block moving. (Take g=9.8 m/s2g = 9.8\ \text{m/s}^2.)

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Given: mass m=10 kgm = 10\ \text{kg}, coefficient of static friction μs=0.4\mu_s = 0.4, g=9.8 m/s2g = 9.8\ \text{m/s}^2. On a horizontal floor the normal reaction equals the weight, N=mg=10×9.8=98 NN = mg = 10 \times 9.8 = 98\ \text{N}.\n\nThe maximum static friction the floor can supply is fs(max)=μsN=0.4×98=39.2 Nf_{s(\text{max})} = \mu_s N = 0.4 \times 98 = 39.2\ \text{N}\n\nThe applied horizontal push is only 30 N30\ \text{N}, which is less than this maximum of 39.2 N39.2\ \text{N}. Since static friction is self-adjusting -- it rises to match whatever is applied, up to its limiting value -- the actual friction force here adjusts to exactl …

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