Question 30 of 32
Q.A car of mass M moves upward with a constant speed v along an inclined road making an angle θ with the horizontal. If μ be the coefficient of friction between the road and the wheel of the car, show that the power of the engine of the car is P = vMg (sin θ + μ cos θ). OR A balloon at rest on the ground is rising upward with acceleration g/8. A stone is dropped from the balloon when it is at height H. Show that the time taken by the stone to touch the ground is 2√(H/g).
West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★
94% · 30/32 Questions
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Start your 14-day free trial to unlock the full solution →At constant speed, the engine's driving force just balances gravity's component down the slope plus friction; power = force × velocity.
The car of mass moves up the incline (angle ) at constant speed , so its acceleration is zero and the net force along the incline is zero.
Forces along the incline opposing motion:
- Component of weight: (down the slope)
- Friction: (since normal reaction on the incline, opposing motion) …
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