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Q.A car of mass M moves upward with a constant speed v along an inclined road making an angle θ with the horizontal. If μ be the coefficient of friction between the road and the wheel of the car, show that the power of the engine of the car is P = vMg (sin θ + μ cos θ). OR A balloon at rest on the ground is rising upward with acceleration g/8. A stone is dropped from the balloon when it is at height H. Show that the time taken by the stone to touch the ground is 2√(H/g).

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★
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At constant speed, the engine's driving force just balances gravity's component down the slope plus friction; power = force × velocity.

The car of mass MM moves up the incline (angle θ\theta) at constant speed vv, so its acceleration is zero and the net force along the incline is zero.

Forces along the incline opposing motion:

  • Component of weight: Mgsin⁡θMg\sin\theta (down the slope)
  • Friction: f=μN=μMgcos⁡θf=\mu N=\mu Mg\cos\theta (since normal reaction N=Mgcos⁡θN=Mg\cos\theta on the incline, opposing motion) …

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