Physics · Ch 6 — System of Particles and Rotational Motion
Motion of the Centre of Mass and Conservation of Linear Momentum
Motion of the Centre of Mass and Conservation of Linear Momentum
Differentiating the defining formula (Section 5.3) once with respect
to time, and using as a constant (no mass enters or leaves the system),
The right-hand side is nothing but the total linear momentum of the system -- the vector sum
of the momenta of every individual particle. So : the total momentum of any system
of particles equals the total mass times the velocity of its own centre of mass, exactly as though the
whole system were one single particle of mass moving with velocity .
Differentiating once more,
Now, the force on each particle can always be split into an external part (from outside the
system) and an internal part (from every other particle within the system). By Newton's third law, every
internal force comes in an equal-and-opposite pair between two particles of the system, so when the sum
is taken over the WHOLE system, every internal force pair cancels exactly, leaving only
the net external force:
This is the central result of this section: the centre of mass of any system of particles moves exactly as a single particle of mass would move under the net external force alone -- entirely independent
of whatever internal forces (a string pulling two blocks together, an explosive charge, the mutual
gravitational pull between the particles) may also be acting within the system. An explosion that splits a
shell into several fragments, for instance, involves only internal forces between the fragments at the
instant of the explosion; the shell's centre of mass therefore continues, completely undisturbed, along
the very same trajectory the shell was already following, right through the instant of the explosion,
exactly as illustrated in this chapter's worked example of a shell bursting into two pieces mid-flight.
Conservation of linear momentum follows immediately as the special case : if no net …