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Physics · Ch 6 — System of Particles and Rotational Motion

Summary

Summary

Centre of mass of a two-particle system, R⃗=(m1r⃗1+m2r⃗2)/(m1+m2)\vec R = (m_1\vec r_1+m_2\vec r_2)/(m_1+m_2), extends to any system of particles or rigid body, R⃗=∑mir⃗i/M\vec R = \sum m_i\vec r_i / M, and need not lie inside the body's own material (e.g. a ring). Motion of the centre of mass: Ma⃗cm=F⃗extM\vec a_{cm} = \vec F_{ext}, so internal forces (an explosion, a collision) never move the centre of mass off its original path; when F⃗ext=0\vec F_{ext}=0, total linear momentum is conserved. Torque, τ⃗=r⃗×F⃗\vec\tau = \vec r\times\vec F, is the rotational analogue of force. Angular momentum, l⃗=r⃗×p⃗\vec l = \vec r\times\vec p for a particle, obeys dL⃗/dt=τ⃗extd\vec L/dt = \vec\tau_{ext}; when τ⃗ext=0\vec\tau_{ext}=0, L⃗\vec L is conserved (a spinning skater pulling in the arms). A rigid body is in equilibrium only when both net force and net torque are zero; a lever balances under the principle of moments, F1d1=F2d2F_1d_1=F_2d_2; a couple has zero net force but a nonzero moment FdFd. Centre of gravity coincides with centre of mass in a uniform gravitational field. Moment of inertia, I=∑miri2I=\sum m_ir_i^2, is the rotational analogue of mass, depending on the axis; standard values are quoted for a rod, ring, disc, sphere and cylinder. Radius of gyration, K=I/MK=\sqrt{I/M}. The theorem of parallel axes, I=Icm+Md2I=I_{cm}+Md^2, and the theorem of perpendicular axes (planar bodies only), Iz=Ix+IyI_z=I_x+I_y, exte …