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Example · Example 1

Q.Two point masses m1=2 kgm_1 = 2\ \text{kg} and m2=3 kgm_2 = 3\ \text{kg} lie on the xx-axis at x1=0x_1 = 0 and x2=5 mx_2 = 5\ \text{m} respectively. Locate the centre of mass of this two-particle system.

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✓ Free question

Using xcm=m1x1+m2x2m1+m2x_{cm} = \dfrac{m_1x_1 + m_2x_2}{m_1+m_2} with m1=2 kgm_1=2\ \text{kg}, x1=0x_1=0, m2=3 kgm_2=3\ \text{kg}, x2=5 mx_2=5\ \text{m}:

xcm=2(0)+3(5)2+3=155=3 mx_{cm} = \frac{2(0) + 3(5)}{2+3} = \frac{15}{5} = 3\ \text{m}

The centre of mass lies at x=3 mx = 3\ \text{m}, which is 3 m3\ \text{m} from m1m_1 and 2 m2\ \text{m} from m2m_2 -- closer to the heavier mass m2m_2, exactly as expected.

✓Final answer

xcm=3 mx_{cm} = 3\ \text{m} from the origin (closer to m2=3 kgm_2 = 3\ \text{kg}).

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