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Exercises · Q10

Q.Using the same data as Exercise Question 2 (x:2,3,5,4,6x:2,3,5,4,6; y:3,4,2,5,6y:3,4,2,5,6), find the two regression coefficients byxb_{yx} and bxyb_{xy}, and verify that r2=byxbxyr^2=b_{yx}b_{xy} using the value of rr found there.

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From Exercise Question 2, ∑(x−xˉ)(y−yˉ)=4\sum(x-\bar x)(y-\bar y)=4, ∑(x−xˉ)2=10\sum(x-\bar x)^2=10, ∑(y−yˉ)2=10\sum(y-\bar y)^2=10.

Step 1 — Apply the regression-coefficient formulas.

byx=∑(x−xˉ)(y−yˉ)∑(x−xˉ)2=410=0.4b_{yx} = \dfrac{\sum(x-\bar x)(y-\bar y)}{\sum(x-\bar x)^2} = \dfrac{4}{10} = 0.4

bxy=∑(x−xˉ)(y−yˉ)∑(y−yˉ)2=410=0.4b_{xy} = \dfrac{\sum(x-\bar x)(y-\bar y)}{\sum(y-\bar y)^2} = \dfrac{4}{10} = 0.4

(Both come out equal here purely because ∑(x−xˉ)2=∑(y−yˉ)2=10\sum(x-\bar x)^2=\sum(y-\bar y)^2=10 for this particular data — not a general rule.)

Step 2 — Verify r2=byxbxyr^2=b_{yx}b_{xy}. byx×bxy=0.4×0.4=0.16b_{yx}\times b_{xy} = 0.4\times0.4=0.16. From Exercise Question 2, r=0.4r=0.4, so r2=0.16r^2=0.16 — matches exactly. …

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