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Worked Examples · Example 5

Q.Using the same advertising expenditure and sales data as Worked Examples 1 and 2 (covariance =1.2=1.2, Var(x)=2\text{Var}(x)=2, Var(y)=1.2\text{Var}(y)=1.2), find the two regression coefficients byxb_{yx} and bxyb_{xy}, and verify the relation r2=byx⋅bxyr^2 = b_{yx}\cdot b_{xy} using the value of rr found in Worked Example 2.

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Step 1 — Apply the two regression-coefficient formulas. Using Cov(x,y)=1.2\text{Cov}(x,y)=1.2, Var(x)=2\text{Var}(x)=2, Var(y)=1.2\text{Var}(y)=1.2 from Worked Examples 1–2:

byx=Cov(x,y)Var(x)=1.22=0.6b_{yx} = \dfrac{\text{Cov}(x,y)}{\text{Var}(x)} = \dfrac{1.2}{2} = 0.6

bxy=Cov(x,y)Var(y)=1.21.2=1.0b_{xy} = \dfrac{\text{Cov}(x,y)}{\text{Var}(y)} = \dfrac{1.2}{1.2} = 1.0

Step 2 — Verify r2=byx⋅bxyr^2 = b_{yx}\cdot b_{xy}. byx×bxy=0.6×1.0=0.6b_{yx}\times b_{xy} = 0.6\times1.0 = 0.6. From Worked Example 2, r=6/60r = 6/\sqrt{60}, so exactly, r2=36/60=0.6r^2 = 36/60 = 0.6 — matching byx⋅bxyb_{yx}\cdot b_{xy} precisely (not just approximately, since both were computed from exact fractions before rounding). …

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