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Worked Examples · Example 4
Q.

The ranks given by two examiners, A and B, to 6 candidates in an interview are shown below. Find Spearman's rank correlation coefficient between the two examiners' rankings.

Candidate123456
Rank by Examiner A123456
Rank by Examiner B214365
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Both examiners' ranks are already given directly (1 to 6, no ties), so Spearman's formula can be applied immediately.

Step 1 — Find d=RA−RBd = R_A - R_B for each candidate.

CandidateRAR_ARBR_Bd=RA−RBd=R_A-R_Bd2d^2
112−11
22111
334−11
44311
556−11
66511
Total6

∑d2=6\sum d^2 = 6.

Step 2 — Apply the formula, with n=6n=6.

rs=1−6∑d2n(n2−1)=1−6×66×(36−1)=1−366×35=1−36210r_s = 1 - \dfrac{6\sum d^2}{n(n^2-1)} = 1 - \dfrac{6\times6}{6\times(36-1)} = 1 - \dfrac{36}{6\times35} = 1 - \dfrac{36}{210}

Step 3 — Simplify. 36210=635≈0.1714\dfrac{36}{210} = \dfrac{6}{35} \approx 0.1714, so rs≈1−0.1714=0.8286r_s \approx 1 - 0.1714 = 0.8286. …

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