If $A=\begin{pmatrix}2&-3\\0&4\end{pmatrix}$, find $3A$ and $-2A$.

If A= 2-3; 04 , find 3A and -2A.

Worked Examples · Example 5

A=\begin{pmatrix}2&-3\\0&4\end{pmatrix}

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$3A$

3A = 3\begin{pmatrix}2&-3\\0&4\end{pmatrix} = \begin{pmatrix}3(2)&3(-3)\\3(0)&3(4)\end{pmatrix} = \begin{pmatrix}6&-9\\0&12\end{pmatrix}

$-2A$

$-2A = -2\begin{pmatrix}2&-3\\0&4\end{pmatrix} = \begin{pmatrix}-2(2)&-2(-3)\\-2(0)&-2(4)\end{pmatrix} = \begin{pmatrix}-4&6\\0&-8\end{pmatrix}$ …