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Example · Example 10

Q.The vapour pressure of pure water at 298 K298\ \text{K} is 23.8 mm Hg23.8\ \text{mm Hg}. Using the relative lowering of vapour pressure found for the urea solution of the previous example, calculate the actual vapour pressure of that solution.

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The relative lowering found previously was 0.1/10.1≈0.0099010.1/10.1 \approx 0.009901. The actual lowering is Δp=0.009901×23.8 mm Hg≈0.2356 mm Hg\Delta p = 0.009901 \times 23.8\ \text{mm Hg} \approx 0.2356\ \text{mm Hg}. The vapour pressure of the solution is therefore p1=p1∘−Δp=23.8−0.2356≈23.564 mm Hgp_1 = p_1^{\circ} - \Delta p = 23.8 - 0.2356 \approx 23.564\ \text{mm Hg}. [!ANSWER] T …

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