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Mathematics · Ch 6 — Application of Derivatives

Summary

Summary

Rate of change. If y=f(x)y = f(x) and both vary with time tt, dydt=f′(x)⋅dxdt\dfrac{dy}{dt} = f'(x)\cdot\dfrac{dx}{dt} (related rates, via the chain rule); a positive rate means increasing, a negative rate means decreasing.

Increasing/decreasing. With ff continuous on [a,b][a,b], differentiable on (a,b)(a,b): f′(x)>0f'(x) > 0 throughout ⇒\Rightarrow increasing; f′(x)<0f'(x) < 0 throughout ⇒\Rightarrow decreasing; f′(x)=0f'(x) = 0 throughout ⇒\Rightarrow constant. Intervals are found by solving f′(x)=0f'(x) = 0 for critical points, then sign-testing f′f' on each resulting interval.

Tangent and normal to y=f(x)y = f(x) at (x0,y0)(x_0, y_0):

tangent: y−y0=f′(x0)(x−x0),normal: y−y0=−1f′(x0)(x−x0)  (f′(x0)≠0).\text{tangent: } y - y_0 = f'(x_0)(x-x_0), \qquad \text{normal: } y-y_0 = -\frac{1}{f'(x_0)}(x-x_0)\ \ (f'(x_0)\ne0).

If f′(x0)=0f'(x_0)=0: the tangent is y=y0y=y_0 (horizontal) and the normal is x=x0x=x_0 (vertical).

Local maxima/minima -- critical points. Occur only where f′(c)=0f'(c)=0 or f′(c)f'(c) fails to exist.

First derivative test (geometric): f′f' changes +→−+\to- at cc ⇒\Rightarrow local max; −→+-\to+ ⇒\Rightarrow local min; no sign change ⇒\Rightarrow neither.

Second derivative test (given as a provable tool, via concavity): at a critical point with f′(c)=0f'(c)=0: f′′(c)<0⇒f''(c)<0 \Rightarrow local max; f′′(c)>0⇒f''(c)>0 \Rightarrow local min; f′′(c)=0⇒f''(c)=0 \Rightarrow inconclusive, use the first derivative test instead. …