Mathematics · Class 12 Science
Ch 11Applications of the Integrals — Class 12 Mathematics, concept-first.
Until now, the definite integral has mostly been a number you compute by finding an antiderivative and applying the Fundamental Theorem of Calculus. This chapter gives that number a geometric meaning: when throughout , the definite integral equals the exact area of the region bounded above by the curve , below by the -…
Key concepts
Hover a concept to preview it and jump to its most relevant Q&A.
Area between Two Curves
When two curves and cross each other, they enclose a bounded region between them. To find its area, the first step is always to locate the points where the two curves meet, by solving their equations simultaneously -- th…
Most relevant Q&A
- Find the area of the region bounded by the circle $x^2 + y^2 = 16$ and the line $x = 2$, lying to the right of the line $x = 2$.Free
- Find the area of the region bounded by the curve $y = x^2$ and the line $y = x$.Preview
- Find the area of the region bounded by the parabola $y = x^2$ and the line $y = 4$.Free
- Find the area of the region bounded by the parabola $x^2 = y$ and the line $y = x + 2$.Preview
- Find the area of the smaller region bounded by the ellipse $\dfrac{x^2}{9} + \dfrac{y^2}{4} = 1$ and the line $\dfrac{x}{3} + \dfrac{y}{2} =…Preview
Chapter contents
The NCERT structure, section by section. Open a section to see its questions, then read the concept-first solution.
The Area-Under-a-Curve Idea
Until now, the definite integral has mostly been a number you compute by finding an antiderivative and applying the Fundamental Theorem of Calculus.
Area Under a Straight Line
The simplest curve to which the area idea of Section 1 applies is a straight line . Suppose the line stays at or above the -axis for every in (with ).
Area of a Circle (Standard Form)
The standard equation of a circle of radius centred at the origin is . Solving for , the upper half of the circle is the curve and the full circle's area is derived by integrating this expression and…
Area Under a Parabola (Standard Form)
A parabola in standard form, such as (opening to the right, vertex at the origin, with ), is not a function of by itself -- solving for gives two branches, , symmetric about the -axis.
Area of an Ellipse (Standard Form)
The standard equation of an ellipse centred at the origin, with semi-axes (along ) and (along ), is . Solving for the upper half, Notice that this is exactly the circle's semicircle expression (a circ…
Area Between Two Curves
Sections 2-5 each found the area under a single curve. Many exam questions instead ask for the area of a region enclosed between two curves -- most commonly a line and a parabola, or a line and an ell…
Summary
The core idea. For on , the definite integral equals the area bounded by , the -axis, and the ordinates -- justified by the Riemann-sum limit of thin rectangular strips.
Sample & Board Papers
Sample papers and previous-year board questions for this subject.
+−Show 8 questionsHide questions8 questions
- Q1Using integral calculus, find the area of x^2/2 + y^2/1 = 1.Preview
- Q2Find the area of the circle x² + y² = 16 using integral calculus.Preview
- Q3Find the area bounded by y = x, x = 2 and x-axis. (using calculus)Preview
- Q4Find the area of circle x² + y² = 8x using calculus.Preview
- Q5Find the area of the triangle formed by y = 4x, x-axis and x = 4. (using Calculus)Preview
- Q6Find the area bounded by the curve y=sinx, x=0, x=π and the x-axis.Preview
- Q7Find the area of the region bounded by the curves $y = \sqrt{x}$, $2y - x + 3 = 0$, $x$-axis and lying in the first quadrant.Preview
- Q8Find the area in the first quadrant enclosed by the $x$-axis, the line $x = \sqrt{3}\,y$ and the circle $x^2 + y^2 = 4$, using definite inte…Preview
More questions
25 Q+−Show 3 questionsHide questions3 questions
- Q23Find the area of the region bounded by the circle $x^2 + y^2 = 16$ and the line $x = 2$, lying to the right of the line $x = 2$.Free
- Q24Find the area of the region bounded by the line $y = 3x$, the $y$-axis, and the line $y = 6$.Preview
- Q25Find the whole area of the ellipse $9x^2 + 25y^2 = 225$, using integration.Preview
+−Show 7 questionsHide questions7 questions
- Example 1Find the area of the region bounded by the line $y = 3x + 1$, the $x$-axis, and the ordinates $x = 1$ and $x = 3$.Free
- Example 2Find the area of the region bounded by the circle $x^2 + y^2 = 25$ and the $x$-axis, lying above the $x$-axis.Free
- Example 3Find the area enclosed by the circle $x^2 + y^2 = 4$, using integration.Free
- Example 4Find the area of the region bounded by the parabola $y^2 = 8x$ and its latus rectum (the line $x = 2$).Preview
- Example 5Find the area of the region in the first quadrant bounded by the parabola $y^2 = 4x$, the $y$-axis, and the line $y = 4$.Preview
- Example 6Find the area of the ellipse $\dfrac{x^2}{9} + \dfrac{y^2}{4} = 1$, using integration.Preview
- Example 7Find the area of the region bounded by the curve $y = x^2$ and the line $y = x$.Preview
+−Show 3 questionsHide questions3 questions
- Q8Find the area of the region bounded by the line $y = 2x + 3$, the $x$-axis, and the ordinates $x = 0$ and $x = 2$.Free
- Q9Find the area of the triangle bounded by the line $y = x$, the $x$-axis, and the line $x = 4$, using integration.Preview
- Q10Find the area of the region bounded by the line $3x + 2y = 12$ and the coordinate axes, in the first quadrant.Preview
+−Show 3 questionsHide questions3 questions
+−Show 3 questionsHide questions3 questions
- Q14Find the area of the region bounded by the parabola $y^2 = 4x$ and the line $x = 4$.Free
- Q15Find the area of the region in the first quadrant bounded by the parabola $y^2 = 9x$, the $y$-axis, and the line $y = 6$.Preview
- Q16Find the area of the region bounded by the parabola $y^2 = 16x$ and its latus rectum.Preview
+−Show 3 questionsHide questions3 questions
- Q17Find the area of the ellipse $\dfrac{x^2}{25} + \dfrac{y^2}{16} = 1$, using integration.Free
- Q18Find the area of the ellipse $4x^2 + 9y^2 = 36$, using integration.Preview
- Q19Find the area of the region in the first quadrant bounded by the ellipse $\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1$, using integration.Preview
+−Show 3 questionsHide questions3 questions
- Q20Find the area of the region bounded by the parabola $y = x^2$ and the line $y = 4$.Free
- Q21Find the area of the region bounded by the parabola $x^2 = y$ and the line $y = x + 2$.Preview
- Q22Find the area of the smaller region bounded by the ellipse $\dfrac{x^2}{9} + \dfrac{y^2}{4} = 1$ and the line $\dfrac{x}{3} + \dfrac{y}{2} =…Preview