Skip to content
Exercise: Area Between Two Curves · Q20

Q.Find the area of the region bounded by the parabola y=x2y = x^2 and the line y=4y = 4.

West Bengal WbchseTextbookSubjectiveImportance★★★★★
70% · 23/33 Questions
✓ Free question

The curves meet at x=±2x=\pm2; the horizontal line y=4y=4 lies above the parabola between them.

Setting x2=4x^2=4 gives x=±2x=\pm2. Testing x=0x=0: the line gives y=4y=4 and the parabola gives y=0y=0, so y=4y=4 lies above y=x2y=x^2 throughout (−2,2)(-2,2). By the even symmetry of 4−x24-x^2, the area is

Area=∫−22(4−x2) dx=2∫02(4−x2) dx=2[4x−x33]02=2(8−83)=2⋅163=323.\text{Area} = \int_{-2}^{2}\big(4-x^2\big)\,dx = 2\int_0^2\big(4-x^2\big)\,dx = 2\left[4x-\frac{x^3}{3}\right]_0^2 = 2\left(8-\frac{8}{3}\right) = 2\cdot\frac{16}{3} = \frac{32}{3}.

✓Final answer

The area is 323\boxed{\dfrac{32}{3}} square units.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.