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Exercise: Area Between Two Curves · Q21

Q.Find the area of the region bounded by the parabola x2=yx^2 = y and the line y=x+2y = x + 2.

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The curves meet at x=−1x=-1 and x=2x=2; the line lies above the parabola between them.

Setting x2=x+2x^2=x+2 gives x2−x−2=0⇒(x−2)(x+1)=0x^2-x-2=0 \Rightarrow (x-2)(x+1)=0, so x=−1x=-1 or x=2x=2. Testing x=0x=0: the line gives y=2y=2 and the parabola gives y=0y=0, so the line y=x+2y=x+2 lies above the parabola y=x2y=x^2 throughout (−1,2)(-1,2). The area is

Area=∫−12[(x+2)−x2] dx=[x22+2x−x33]−12.\text{Area} = \int_{-1}^{2}\big[(x+2)-x^2\big]\,dx = \left[\frac{x^2}{2}+2x-\frac{x^3}{3}\right]_{-1}^{2}.

At x=2x=2: 42+4−83=2+4−83=6−83=103\dfrac{4}{2}+4-\dfrac{8}{3} = 2+4-\dfrac{8}{3} = 6-\dfrac{8}{3}=\dfrac{10}{3}. …

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