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Question 62 of 66

Q.If f(x)=log⁡x(log⁡ex)f(x) = \log_x (\log_e x), then the value of f′(e)f'(e) is

(a) ee
(b) 2e\dfrac{2}{e}
(c) 1e\dfrac{1}{e}
(d) 00
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2026MCQ· 1mImportance★★★★★
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Convert to natural logs, differentiate with the quotient rule, and evaluate at x=ex=e where ln⁡x=1, ln⁡(ln⁡x)=0\ln x=1,\ \ln(\ln x)=0.

Differentiating a change-of-base logarithm is a CBSE/NCERT Class 12 continuity and differentiability exercise.

Using change of base, f(x)=log⁡x(log⁡ex)=ln⁡(ln⁡x)ln⁡xf(x)=\log_x(\log_e x) = \dfrac{\ln(\ln x)}{\ln x}.

Let N=ln⁡(ln⁡x)N=\ln(\ln x) and D=ln⁡xD=\ln x. Then

N′=1ln⁡x⋅1x=1xln⁡x,D′=1x.N' = \frac{1}{\ln x}\cdot\frac1x = \frac{1}{x\ln x}, \qquad D' = \frac1x.

Quotient rule: …

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