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Exercise: Total Probability and Bayes... · Q23

Q.A factory has two machines. Machine I produces 60%60\% of the items and Machine II produces 40%40\%. Of their outputs, 2%2\% and 3%3\% are defective respectively. An item is drawn at random and found to be defective. Find the probability that it was produced by Machine II.

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P(D)=0.6×0.02+0.4×0.03=0.012+0.012=0.024P(D)=0.6\times0.02+0.4\times0.03=0.012+0.012=0.024. P(II∩D)=0.4×0.03=0.012P(\text{II}\cap D)=0.4\times0.03=0.012. By Bayes' theorem, P(II∣D)=0.0120.024=0.5P(\text{II}\mid D)=\dfrac{0.012}{0.024}=0.5. [!ANSWER] $P(\tex …

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