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Miscellaneous · Q36

Q.A box contains 33 defective and 77 non-defective items. Two items are selected at random without replacement. Let XX denote the number of defective items selected. Find the probability distribution of XX and hence find its mean.

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Concept understanding — Mean and Variance of a Random Variable

Mean and Variance of a Random Variable

A random variable XX assigns a number to each outcome, and its probability distribution lists each value xix_i with its probability pip_i (all pi≥0p_i\ge 0 and ∑pi=1\sum p_i=1).

Mean (expected value)

The mean μ=E(X)\mu=E(X) is the long-run average -- a weighted average of the values, each weighted by its probability:

E(X)=∑xi pi.E(X)=\sum x_i\,p_i.

For a function such as X2X^2, weight the function's values: E(X2)=∑xi 2 piE(X^2)=\sum x_i^{\,2}\,p_i.

Variance and standard deviation

Variance measures the spread about the mean. The working formula is:

Var⁡(X)=E(X2)−[E(X)]2=∑xi 2pi−μ2,\operatorname{Var}(X)=E(X^2)-\big[E(X)\big]^2=\sum x_i^{\,2}p_i-\mu^2,

and the standard deviation is σ=Var⁡(X)\sigma=\sqrt{\operatorname{Var}(X)} (back in the original units). …

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