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Exercise: Coordinates and Distance · Q13

Q.If the distance between the points A(k,2,1)A(k,2,1) and B(2,−1,3)B(2,-1,3) is 14\sqrt{14}, find the value(s) of kk.

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AB2=(2−k)2+(−1−2)2+(3−1)2=(2−k)2+9+4=(2−k)2+13.AB^2=(2-k)^2+(-1-2)^2+(3-1)^2=(2-k)^2+9+4=(2-k)^2+13.

Given AB=14AB=\sqrt{14}, so AB2=14AB^2=14:

(2−k)2+13=14⇒(2−k)2=1⇒2−k=±1.(2-k)^2+13=14 \quad\Rightarrow\quad (2-k)^2=1 \quad\Rightarrow\quad 2-k=\pm1. …

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