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Exercise: Equation of a Line · Q19

Q.Find the Cartesian equation of the line passing through the points (1,−2,3)(1,-2,3) and (4,0,−3)(4,0,-3).

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✓ Free question

Direction ratios: 4−1, 0−(−2), −3−3=3,2,−64-1,\ 0-(-2),\ -3-3 = 3,2,-6.

Using (1,−2,3)(1,-2,3) as the base point:

x−13=y−(−2)2=z−3−6⇒x−13=y+22=z−3−6.\frac{x-1}{3}=\frac{y-(-2)}{2}=\frac{z-3}{-6} \quad\Rightarrow\quad \frac{x-1}{3}=\frac{y+2}{2}=\frac{z-3}{-6}.

✓Final answer

x−13=y+22=z−3−6\dfrac{x-1}{3}=\dfrac{y+2}{2}=\dfrac{z-3}{-6}

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