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Numerical · Q26

Q.The stopping potential for photoelectrons emitted from a metal surface under a certain illumination is measured to be 1.5 V1.5\ \text{V}. Calculate the maximum kinetic energy of the emitted photoelectrons, in both electron-volts and joules.

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Relation. By definition of the stopping potential, the work done by the retarding field on the fastest photoelectron exactly equals that electron's maximum kinetic energy: Kmax=eV0K_{max}=eV_0.

In electron-volts. With V0=1.5 VV_0=1.5\ \text{V}, Kmax=1.5 eVK_{max}=1.5\ \text{eV} directly, since an electron crossing a potential difference of 1.5 V1.5\ \text{V} gains exactly 1.5 eV1.5\ \text{eV} of energy by definition of the …

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