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Question 27 of 42

Q.Write down Einstein's photoelectric equation and mention the symbols used. The photoelectric threshold wavelength for a certain metal is 400 nm. Find the maximum kinetic energy of the emitted electrons from the metal surface by ultraviolet light of wavelength 200 nm. Given, h = 6.63×10⁻³⁴ J.s.

West Bengal WbchseWest Bengal HS (WBCHSE) Board 2016Subjective· 3mImportance★★★★★
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By Einstein's photoelectric equation, KE_max = hc/λ − hc/λ₀; using the given threshold wavelength (400 nm) and incident wavelength (200 nm) gives about 3.1 eV.

Einstein's photoelectric equation: When light of frequency ν (greater than the threshold frequency ν₀) falls on a metal, each absorbed photon of energy hν ejects an electron, giving it maximum kinetic energy

KE_max = hν − hν₀ = hν − W₀

where W₀ = hν₀ is the work function of the metal (the minimum energy needed to free an electron from the surface), h is Planck's constant, ν is the frequency of incident light, and ν₀ is the threshold frequency (corresponding to threshold wavelength λ₀).

In terms of wavelength: KE_max = hc/λ − hc/λ₀ = hc(1/λ − 1/λ₀)

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