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Question 33 of 42

Q.A charge Q is placed at the centre of the line joining two charges +q and +q. The system will be in equilibrium if Q is

(a) -q
(b) -q/2
(c) -q/3
(d) -q/4
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023MCQ· 1mImportance★★★★★
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For the middle charge to balance one end charge, its attraction must equal the repulsion from the far end charge; solving gives Q = -q/4.

Place the two +q charges at the ends, distance 2d2d apart, and Q at the centre (distance dd from each). Consider the equilibrium of one end charge (say the left +q):

  • Repulsion from the other end charge (+q), separation 2d2d: F1=kq2(2d)2=kq24d2F_1 = \dfrac{kq^2}{(2d)^2} = \dfrac{kq^2}{4d^2} (pushing it further away).
  • Force from Q, separation dd: F2=k∣Q∣qd2F_2 = \dfrac{k|Q|q}{d^2}. …

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