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Example · Example 3

Q.Two point charges of +3×10−6 C+3\times10^{-6}\ \text{C} and −5×10−6 C-5\times10^{-6}\ \text{C} are placed 0.4 m0.4\ \text{m} apart in vacuum. Calculate the magnitude of the force between them and state whether it is attractive or repulsive.

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✓ Free question

Given q1=+3×10−6 Cq_1=+3\times10^{-6}\ \text{C}, q2=−5×10−6 Cq_2=-5\times10^{-6}\ \text{C}, r=0.4 mr=0.4\ \text{m}.

F=k∣q1∣∣q2∣r2=(9×109)(3×10−6)(5×10−6)(0.4)2F = \frac{k|q_1||q_2|}{r^2} = \frac{(9\times10^9)(3\times10^{-6})(5\times10^{-6})}{(0.4)^2}

Numerator: 9×109×3×10−6=2.7×1049\times10^9\times3\times10^{-6}=2.7\times10^4; then 2.7×104×5×10−6=0.1352.7\times10^4\times5\times10^{-6}=0.135.

Denominator: (0.4)2=0.16(0.4)^2=0.16.

F=0.1350.16≈0.84 NF = \frac{0.135}{0.16} \approx 0.84\ \text{N}

Since q1q_1 is positive and q2q_2 is negative, the force is attractive.

✓Final answer

The force is approximately 0.84 N0.84\ \text{N}, and it is attractive.

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