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Numerical · Q20

Q.A radioactive sample initially contains N0=8×1010N_0 = 8\times10^{10} atoms and has a half-life of 2020 days. Find the number of atoms remaining after 6060 days.

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✓ Free question

Since the half-life is 2020 days, 6060 days corresponds to exactly

6020=3 half-lives\frac{60}{20} = 3 \text{ half-lives}

Each half-life halves the remaining population, so after 33 half-lives,

N=N023=8×10108=1×1010 atomsN = \frac{N_0}{2^3} = \frac{8\times10^{10}}{8} = 1\times10^{10}\ \text{atoms}

✓Final answer

N=1×1010N = 1\times10^{10} atoms.

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