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Exercise 13.1 · Q13

Q.An instructor has a question bank consisting of 300 easy True / False questions, 200 difficult True / False questions, 500 easy multiple choice questions and 400 difficult multiple choice questions. If a question is selected at random from the question bank, what is the probability that it will be an easy question given that it is a multiple choice question?

Yanam BieapTextbookSubjective· 3mImportance★★★★★
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The problem asks for the conditional probability that a randomly selected question is easy, given that it is a multiple choice question. Using the definition of conditional probability, we find the answer is 59\frac{5}{9}.

The core idea here is conditional probability: the probability of event AA happening given that event BB has already occurred. The formula is:

P(A∣B)=P(A∩B)P(B)P(A \mid B) = \frac{P(A \cap B)}{P(B)}

In this problem, we want P(Easy∣Multiple Choice)P(\text{Easy} \mid \text{Multiple Choice}). That means we restrict our attention only to multiple choice questions, and then ask: what fraction of those are easy?

Let’s break it down step by step.

  1. Organize the data.

    The question bank has four categories. Let’s list them clearly:

    TypeEasyDifficultTotal
    True/False300200500
    Multiple Choice500400900
    Total8006001400

    The total number of questions is 300+200+500+400=1400300 + 200 + 500 + 400 = 1400.

  2. Identify the events.

    Let EE be the event that a question is easy.

    Let MM be the event that a question is multiple choice.

    We need P(E∣M)P(E \mid M).

  3. Find P(M)P(M) — the probability that a randomly selected question is multiple choice.

    From the table, the total number of multiple choice questions is 500+400=900500 + 400 = 900.

    So:

P(M)=9001400=914P(M) = \frac{900}{1400} = \frac{9}{14}

  1. Find P(E∩M)P(E \cap M) — the probability that a question is both easy and multiple choice. The number of easy multiple choice questions is 500500. So:

P(E∩M)=5001400=514P(E \cap M) = \frac{500}{1400} = \frac{5}{14}

  1. Apply the conditional probability formula. …

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