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Exercise 5.1 · Q1

Q.If for a sequence Sn=2n−3S_n = 2n-3, then the common difference is:

(a) −1-1
(b) 22
(c) −2-2
(d) 33
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✓ Free question

Given the general (nnth) term of a sequence as a linear function of nn, the common difference is found by subtracting consecutive terms — confirming this sequence is indeed an A.P.

For a sequence with nnth term ana_n, the common difference (if it is an A.P.) is

d=an+1−an(constant for all n)d = a_{n+1} - a_n \quad (\text{constant for all } n)

  1. Given: Sn=2n−3S_n = 2n - 3 (the nnth term of the sequence).
  2. Write the next term, replacing nn by n+1n+1:

Sn+1=2(n+1)−3=2n+2−3=2n−1S_{n+1} = 2(n+1) - 3 = 2n+2-3 = 2n-1

  1. Compute the common difference:

d=Sn+1−Sn=(2n−1)−(2n−3)=2n−1−2n+3=2d = S_{n+1} - S_n = (2n-1) - (2n-3) = 2n-1-2n+3 = 2

  1. Check constancy: since d=2d=2 does not depend on nn, the sequence is confirmed to be an A.P. with common difference 22.
  2. Verify against the options: (a) −1-1 ✗, (b) 22 ✓, (c) −2-2 ✗, (d) 33 ✗.
✓Final answer

The common difference is d=2d = 2 — option (b)

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