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Exercise 5.1 · Q9

Q.Find the sum of all natural numbers between 100 and 300 which are divisible by 4.

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The multiples of 4 strictly between 100 and 300 form the A.P. 104,108,…,296104,108,\ldots,296; its sum is 98009800.

For an A.P. with first term aa, common difference dd, and nn terms: nnth term an=a+(n−1)da_n=a+(n-1)d; sum of nn terms Sn=n2(a+an)S_n=\dfrac{n}{2}(a+a_n).

  1. The multiples of 4 between 100 and 300 start at a=104a=104 (first multiple of 4 greater than 100) and end at l=296l=296 (last multiple of 4 less than 300), with d=4d=4. …

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