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Exercise 5.1 · Q17

Q.Find the middle terms in the A.P. 5,8,11,14,…5, 8, 11, 14, \ldots whose last term is 95.

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The A.P. 5,8,11,14,…,955,8,11,14,\ldots,95 has 3131 terms (odd), so it has one middle term, the 1616th term, equal to 5050.

nnth term: an=a+(n−1)da_n=a+(n-1)d. If the number of terms nn is odd, the unique middle term is the (n+12)\left(\dfrac{n+1}{2}\right)th term.

  1. Here a=5a=5, d=8−5=3d=8-5=3, last term l=95l=95.
  2. Number of terms: 95=5+(n−1)3⇒(n−1)=903=30⇒n=3195=5+(n-1)3\Rightarrow (n-1)=\dfrac{90}{3}=30\Rightarrow n=31. …

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