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Exercise 5.1 · Q6

Q.Write the first five terms of the sequence in which a1=3a_1 = 3, an=3an−1+2a_n = 3a_{n-1} + 2 for n>1n > 1.

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Each term (from the second onward) is generated by applying the recurrence an=3an−1+2a_n=3a_{n-1}+2 to the previous term, starting from a1=3a_1=3.

Recursively-defined sequence:

a1=3,an=3an−1+2  (n>1)a_1 = 3, \qquad a_n = 3a_{n-1}+2 \ \ (n>1)

  1. First term (given):

a1=3a_1 = 3

  1. Second term, using n=2n=2:

a2=3a1+2=3(3)+2=9+2=11a_2 = 3a_1+2 = 3(3)+2 = 9+2 = 11

  1. Third term, using n=3n=3:

a3=3a2+2=3(11)+2=33+2=35a_3 = 3a_2+2 = 3(11)+2 = 33+2 = 35

  1. Fourth term, using n=4n=4:

a4=3a3+2=3(35)+2=105+2=107a_4 = 3a_3+2 = 3(35)+2 = 105+2 = 107

  1. Fifth term, using n=5n=5: a5=3a4+2=3(107)+2=321+2=323a_5 = 3a_4+2 = 3(107)+2 = 321+2 = 323 …

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