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NCERT Exemplar · Q27

Q.Identify compounds A, B and C in the following reaction: CH3-Br reacts with Mg in dry ether to give A; A is then treated with

(i) CO2 and
(ii) water to give B; B is heated with CH3OH in the presence of H(+) to give C.
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This is a classic Grignard carboxylation followed by esterification: A = CH3MgBr, B = acetic acid (CH3COOH), C = methyl acetate (CH3COOCH3).

Step 1 - A

An alkyl halide reacts with magnesium in dry ether to form a Grignard reagent.

CH3-Br + Mg --(dry ether)--> CH3MgBr

So A = methylmagnesium bromide.

Step 2 - B

A Grignard reagent adds to CO2; aqueous acidic work-up gives a carboxylic acid with one carbon more than the alkyl group.

CH3MgBr + CO2 --> CH3COOMgBr --(H2O/H+)--> CH3COOH

So B = acetic acid (ethanoic acid).

Step 3 - C …

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