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Q.Consider the given data of a hypothetical small portion of mRNA that codes for a functional polypeptide chain and answer the questions that follow : mRNA 5' – UCAUUACCACGAUUCUUUAAAGA – 3'

(a) How many amino acids will be formed from the given codons, if substitution of 'U' by 'C' takes place at the 5th codon ? Explain your answer.
(b) Write the number of amino acids that would be in the polypeptide synthesised by a similar mRNA as above, where in the fourth codon instead of 'C' there is 'U'. Justify your answer.
CBSECBSE Class XII Board 2024Subjective· 2mImportance★★★★★
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A single base substitution in an mRNA codon can either change one amino acid or introduce a premature stop codon, drastically shortening the polypeptide — the effect depends entirely on which codon is altered and what the new codon codes for.

Let’s first read the given mRNA sequence carefully. It is written as:

5' – UCA UUA CCA CGA UUC UUU AAA GA – 3'

The ribosome reads this in triplets (codons) from the 5' end. So the codons are:

  1. UCA
  2. UUA
  3. CCA
  4. CGA
  5. UUC
  6. UUU
  7. AAA
  8. GA (incomplete — only two bases, so it does not code for an amino acid)

Thus, the original mRNA codes for seven amino acids (codons 1 through 7), with the eighth triplet being incomplete and therefore not translated.

Now, part (a) asks: what happens if the 5th codon (UUC) has its first base 'U' substituted by 'C'? That changes UUC to CUC. According to the standard genetic code, UUC codes for phenylalanine (Phe), while CUC codes for leucine (Leu). Both are normal amino acids — neither is a stop codon. So the substitution simply replaces one amino acid with another. The polypeptide chain will still have seven amino acids, because translation continues normally without interruption.

Note

A substitution that changes one amino acid for another is called a missense mutation. It may or may not affect the protein's function, but it does not change the length of the polypeptide. …

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