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Q.Read the passage given below and answer the questions that follow. In recombinant DNA technology, restriction enzymes are used as they recognize and cut DNA within a specific recognition sequence. BamH I is one such restriction enzyme which binds at the recognition sequence 5' G-G-A-T-C-C 3' and cleaves this sequence between G and G on each strand, whereas Alu I binds at the recognition sequence 5' A-G-C-T 3' and cleaves these sequences between G and C on each strand.

(a) If Alu I is used to cut the given DNA strand, how many DNA fragments would be formed ? Write the sequence of each fragment formed with its polarity. 5' C – C – G – T – A – G – C – T – A – T – C – A – G – C – T – G – G 3' 3' G – G – C – A – T – C – G – A – T – A – G – T – C – G – A – C – C 5'
(b) Which one of the two restriction enzymes BamH I or Alu I will preferably be used on the same given DNA strand to make a recombinant DNA molecule and why ?
(c) After binding to the two strands of the double helix DNA, where specifically does the restriction enzyme act to cut the two strands of DNA ? Write the specific term used for the specific nucleotide sequences of DNA recognised by a restriction endonuclease.
(OR)
(c) Write the specific sequence of DNA segment recognised by the restriction endonuclease EcoRI.
CBSECBSE Class XII Board 2024Subjective· 4mImportance★★★★★
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Part (a): Alu I cuts the duplex at its two AGCT sites into three blunt-ended fragments. Part (b): on this particular strand only Alu I can be used, because the Alu I recognition site (AGCT) is present while the Bam H I recognition site (GGATCC) is absent — so Bam H I cannot cut this DNA at all. Restriction enzymes cut the phosphodiester backbone of both strands at palindromic sequences.

Part (c): EcoRI recognises 5' GAATTC 3' / 3' CTTAAG 5'.

Restriction enzymes recognise specific sequences and cut DNA there. Alu I recognises 5' A-G-C-T 3' (cutting between G and C, blunt); Bam H I recognises 5' G-G-A-T-C-C 3' (cutting between the two G's, staggered/sticky).

Part (a)

(a) Number and sequence of Alu I fragments. Scanning the top strand 5' C C G T A G C T A T C A G C T G G 3', the sequence AGCT occurs twice (positions 5–8 and 12–15). Cutting between G and C at each site therefore gives three fragments:

FragmentTop strand (5'→3')Bottom strand (3'→5')
1C-C-G-T-A-GG-G-C-A-T-C
2C-T-A-T-C-A-GG-A-T-A-G-T-C
3C-T-G-GG-A-C-C

All are blunt-ended because Alu I cuts both strands at the same position.

(b) Enzyme to be used on THIS strand. The choice here is decided by which enzyme actually has a recognition site in the given sequence, not by the general sticky-end preference. Reading the given strand 5' C-C-G-T-A-G-C-T-A-T-C-A-G-C-T-G-G 3', the Bam H I site 5' G-G-A-T-C-C 3' is not present anywhere in the sequence, so Bam H I cannot bind or cut this DNA at all. The Alu I site 5' A-G-C-T 3', by contrast, is present twice. Therefore Alu I is the enzyme that will be used on this strand to cut it and generate fragments for constructing a recombinant DNA molecule — it is the only one of the two that can act on the given sequence. (In general, sticky-end cutters are convenient for ligation, but that advantage is irrelevant here because Bam H I has no site to cut.) …

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