Skip to content
Question

Q.In a plot of Λm\Lambda_m against the square root of concentration (C1/2C^{1/2}) for strong and weak electrolyte, the value of limiting molar conductivity of a weak electrolyte cannot be obtained graphically. Suggest a way to obtain this value. Also state the related law, if any.

CBSECBSE Class XII Board 2022Subjective· 2mImportance★★★★★
✓ Free question

The limiting molar conductivity Λm0\Lambda_m^0 of a weak electrolyte cannot be found by direct extrapolation of its Λm\Lambda_m vs. C1/2C^{1/2} plot because the curve is steep and nonlinear. Instead, we use Kohlrausch’s law of independent migration of ions: add the known limiting molar conductivities of the constituent ions (obtained from strong electrolytes) to get the weak electrolyte’s Λm0\Lambda_m^0.


Why the graph fails for weak electrolytes

For a strong electrolyte, Λm\Lambda_m decreases linearly with C\sqrt{C} at low concentrations (Kohlrausch’s empirical law). You can extrapolate that straight line back to C=0C = 0 to read Λm0\Lambda_m^0 directly from the intercept.

For a weak electrolyte (like acetic acid), the plot is completely different. As you dilute the solution, dissociation increases sharply — so Λm\Lambda_m rises steeply at very low concentrations. The curve never becomes linear near C=0C = 0, and you cannot reliably extend it to the vertical axis. Any graphical extrapolation would give a value far below the true Λm0\Lambda_m^0.

Watch out

A common mistake is to try drawing a tangent or fitting a straight line to the weak electrolyte’s data. The plot is not linear at any concentration — the curvature is severe because dissociation changes rapidly with dilution. Extrapolation here is guesswork, not science.


The way forward: Kohlrausch’s law

The solution is to avoid the graph entirely and use a theoretical law that works for all electrolytes.

Kohlrausch’s law of independent migration of ions

Λm0=ν+λ+0+ν−λ−0\Lambda_m^0 = \nu_+ \lambda_+^0 + \nu_- \lambda_-^0

where ν+\nu_+ and ν−\nu_- are the numbers of cations and anions per formula unit, and λ+0\lambda_+^0, λ−0\lambda_-^0 are their limiting molar conductivities (at infinite dilution).

The key insight: at infinite dilution, each ion moves independently of its counterion. So the total conductivity is simply the sum of the contributions from each ion — no matter which electrolyte the ion came from.


Step-by-step method

  1. Identify the ions of the weak electrolyte.

    For example, acetic acid (CH3COOH\text{CH}_3\text{COOH}) dissociates into H+\text{H}^+ and CH3COO−\text{CH}_3\text{COO}^-.

  2. Find the limiting molar conductivities of these ions from strong electrolytes that are fully dissociated.

    • λ0(H+)\lambda^0(\text{H}^+) is obtained from a strong acid like HCl:

Λm0(HCl)=λ0(H+)+λ0(Cl−)\Lambda_m^0(\text{HCl}) = \lambda^0(\text{H}^+) + \lambda^0(\text{Cl}^-)

 Since $\Lambda_m^0(\text{HCl})$ and $\lambda^0(\text{Cl}^-)$ are known from experiments, you solve for $\lambda^0(\text{H}^+)$.
  • λ0(CH3COO−)\lambda^0(\text{CH}_3\text{COO}^-) is obtained from a strong salt like sodium acetate (CH3COONa\text{CH}_3\text{COONa}):

Λm0(CH3COONa)=λ0(CH3COO−)+λ0(Na+)\Lambda_m^0(\text{CH}_3\text{COONa}) = \lambda^0(\text{CH}_3\text{COO}^-) + \lambda^0(\text{Na}^+)

 Again, $\Lambda_m^0$ of the salt and $\lambda^0(\text{Na}^+)$ are known, so $\lambda^0(\text{CH}_3\text{COO}^-)$ is found.

3. Add the ionic contributions for the weak electrolyte:

Λm0(CH3COOH)=λ0(H+)+λ0(CH3COO−)\Lambda_m^0(\text{CH}_3\text{COOH}) = \lambda^0(\text{H}^+) + \lambda^0(\text{CH}_3\text{COO}^-)

Tip

You never need to measure the weak electrolyte itself at infinite dilution. The ionic λ0\lambda^0 values are tabulated for common ions — once you have them, you can compute Λm0\Lambda_m^0 for any weak electrolyte by simple addition. This is the power of Kohlrausch’s law.


The law stated

The related law is Kohlrausch’s law of independent migration of ions (1900). It states that at infinite dilution, each ion contributes a fixed amount to the molar conductivity of an electrolyte, independent of the other ion present. Mathematically:

Λm0=∑iνiλi0\Lambda_m^0 = \sum_i \nu_i \lambda_i^0

where ii runs over all ions in the formula unit.

Important

This law is exact at infinite dilution. It fails at finite concentrations because ion-ion interactions become significant — but for the limiting value, it is the only reliable method for weak electrolytes.


✓Final answer

The limiting molar conductivity of a weak electrolyte is obtained by applying Kohlrausch’s law: add the known limiting molar conductivities of its constituent ions, which are determined from strong electrolytes. The value is Λm0=ν+λ+0+ν−λ−0\boxed{\Lambda_m^0 = \nu_+ \lambda_+^0 + \nu_- \lambda_-^0}.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.