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Question

Q.(a)

(i) Silver atom has completely filled d-orbitals in its ground state, it is still considered to be a transition element. Justify the statement.
(ii) Why are EM2+/M∘E^\circ_{M^{2+}/M} values of Mn and Zn more negative than expected ?
(iii) Why do transition metals form alloys ?
(OR)
(b) Answer the following questions on the basis of the figure given below : The figure is a plot of enthalpy of atomisation (ΔaH∘\Delta_aH^\circ / kJ mol−1^{-1}, y-axis) against atomic number (x-axis) showing three curves labelled Series 1, Series 2 and Series 3 (the 3d, 4d and 5d transition series); each curve rises to a maximum near the middle of its series and falls towards the ends, with Series 3 generally the highest and Series 1 the lowest.
(i) Which element in 3d series has lowest enthalpy of atomisation ?
(ii) Why do metals of the second and third series have greater enthalpies of atomisation ?
(iii) Why are enthalpies of atomisation of transition metals quite high ?
CBSECBSE Class XII Board 2022Subjective· 3mImportance★★★★★
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Part (a): Silver is a transition element because AgX2+\ce{Ag^{2+}} has an incomplete 4d94d^9 shell; the EM2+/M∘E^\circ_{M^{2+}/M} values of Mn and Zn are more negative than expected because of the extra stability of the half-filled 3d53d^5 and fully-filled 3d103d^{10} configurations of their M2+M^{2+} ions; transition metals form alloys because their similar atomic sizes let atoms substitute in the lattice. Part (b) (OR): in the 3d series Zn has the lowest enthalpy of atomisation (filled 3d103d^{10}, weak bonding); 4d/5d metals have higher values because their diffuse orbitals overlap more strongly; transition metals in general have high enthalpies of atomisation because many unpaired dd-electrons give strong metallic bonding.


Part (a)

(i) Silver as a transition element

By the IUPAC definition, a transition element has an incomplete dd-subshell either in its ground state or in one of its common oxidation states. Silver's ground state is [Kr] 4d105s1[\text{Kr}]\,4d^{10}5s^1 and its usual +1+1 ion AgX+\ce{Ag^+} is [Kr] 4d10[\text{Kr}]\,4d^{10} — both filled. However, silver also exists in the +2+2 state (for example in AgFX2\ce{AgF2}), where the configuration is [Kr] 4d9[\text{Kr}]\,4d^9, an incomplete dd-subshell. Because it can form a cation with a partly filled dd-subshell, silver is classed as a transition element.

Watch out

A filled dd-subshell in the ground state alone does not exclude an element — the criterion also covers any common oxidation state.

(ii) Why EM2+/M∘E^\circ_{M^{2+}/M} of Mn and Zn is more negative than expected

EM2+/M∘E^\circ_{M^{2+}/M} reflects the tendency of the metal to be reduced from M2+M^{2+}; a more negative value means the M2+M^{2+} ion is unusually stable and reluctant to be reduced.

  • Mn: MnX2+\ce{Mn^{2+}} is [Ar] 3d5[\text{Ar}]\,3d^5, a half-filled subshell that is extra-stable through exchange energy and symmetry. Forming this stable ion is easy, so E∘E^\circ is more negative than the trend.
  • Zn: ZnX2+\ce{Zn^{2+}} is [Ar] 3d10[\text{Ar}]\,3d^{10}, a fully-filled, very stable subshell; again the ion forms readily, giving a more negative E∘E^\circ.

Extra stability of d5d^5 and d10d^{10} comes from: maximum exchange energy (parallel spins) and a symmetrical (spherical) charge distribution that lowers electron–electron repulsion.

(iii) Why transition metals form alloys

Alloy formation is easy because transition metals have:

  1. Similar atomic radii — sizes change only gradually across a series (poor dd-electron shielding), so atoms of different metals fit into the same lattice with little distortion;
  2. Similar metallic bonding and electronic structure — partly filled dd-orbitals give comparable bonding, allowing free mixing in the solid;
  3. Variable oxidation states — electron distribution can adjust to neighbours. …

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