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Q.The relation R in the set {1,2,3}\{1, 2, 3\} given by R={(1,2),(2,1),(1,1)}R = \{(1, 2), (2, 1), (1, 1)\} is (A) symmetric and transitive, but not reflexive (B) reflexive and symmetric, but not transitive (C) symmetric, but neither reflexive nor transitive (D) an equivalence relation

CBSECBSE Class XII Board 2020MCQ· 1mImportance★★★★★
✓ Free question

The relation R={(1,2),(2,1),(1,1)}R = \{(1, 2), (2, 1), (1, 1)\} on the set {1,2,3}\{1, 2, 3\} is symmetric, but it is neither reflexive nor transitive. Therefore, option (C) is correct.

To determine the properties of the given relation RR on the set A={1,2,3}A = \{1, 2, 3\}, we need to check if it satisfies the definitions of reflexivity, symmetry, and transitivity. Understanding these definitions precisely is key to avoiding common errors.

A relation RR on a set AA is:

  • Reflexive if for every element a∈Aa \in A, the ordered pair (a,a)(a, a) is in RR. This means every element must be related to itself.
  • Symmetric if for every pair (a,b)∈R(a, b) \in R, the pair (b,a)(b, a) is also in RR. This means if aa is related to bb, then bb must also be related to aa.
  • Transitive if for every a,b,c∈Aa, b, c \in A, whenever (a,b)∈R(a, b) \in R and (b,c)∈R(b, c) \in R, it must follow that (a,c)∈R(a, c) \in R. This means if aa is related to bb and bb is related to cc, then aa must also be related to cc.

Let's examine R={(1,2),(2,1),(1,1)}R = \{(1, 2), (2, 1), (1, 1)\} on the set A={1,2,3}A = \{1, 2, 3\} step by step.

  1. Check for Reflexivity:

    For RR to be reflexive, every element in AA must be related to itself. That is, (1,1)(1, 1), (2,2)(2, 2), and (3,3)(3, 3) must all be present in RR.

    • We see that (1,1)∈R(1, 1) \in R.
    • However, (2,2)∉R(2, 2) \notin R.
    • Also, (3,3)∉R(3, 3) \notin R. Since (2,2)(2, 2) and (3,3)(3, 3) are not in RR, the relation RR is not reflexive.
  2. Check for Symmetry:

    For RR to be symmetric, for every pair (a,b)∈R(a, b) \in R, the reverse pair (b,a)(b, a) must also be in RR.

    Let's check each pair in RR:

    • For (1,2)∈R(1, 2) \in R, we need to check if (2,1)∈R(2, 1) \in R. Yes, (2,1)∈R(2, 1) \in R.
    • For (2,1)∈R(2, 1) \in R, we need to check if (1,2)∈R(1, 2) \in R. Yes, (1,2)∈R(1, 2) \in R.
    • For (1,1)∈R(1, 1) \in R, we need to check if (1,1)∈R(1, 1) \in R. Yes, (1,1)∈R(1, 1) \in R. Since for every ordered pair (a,b)(a, b) in RR, the pair (b,a)(b, a) is also in RR, the relation RR is symmetric.
  3. Check for Transitivity:

    For RR to be transitive, if (a,b)∈R(a, b) \in R and (b,c)∈R(b, c) \in R, then (a,c)(a, c) must also be in RR. We need to check all such combinations.

    • Consider (1,2)∈R(1, 2) \in R and (2,1)∈R(2, 1) \in R. Here, a=1,b=2,c=1a=1, b=2, c=1. According to the definition of transitivity, (a,c)=(1,1)(a, c) = (1, 1) must be in RR. We see that (1,1)∈R(1, 1) \in R. This case holds.
    • Consider (2,1)∈R(2, 1) \in R and (1,2)∈R(1, 2) \in R. Here, a=2,b=1,c=2a=2, b=1, c=2. According to the definition of transitivity, (a,c)=(2,2)(a, c) = (2, 2) must be in RR. However, we found earlier that (2,2)∉R(2, 2) \notin R. Since we found a case where (2,1)∈R(2, 1) \in R and (1,2)∈R(1, 2) \in R, but (2,2)∉R(2, 2) \notin R, the relation RR is not transitive.
    Watch out

    A common mistake when checking transitivity is to only look for pairs that "chain" and forget to check if the resulting pair exists. If even one such chain (a,b),(b,c)(a,b), (b,c) exists where (a,c)(a,c) is missing, the relation is not transitive.

In summary:

  • RR is not reflexive.
  • RR is symmetric.
  • RR is not transitive.

Now, let's compare these findings with the given options:

(A) symmetric and transitive, but not reflexive (Incorrect, not transitive)

(B) reflexive and symmetric, but not transitive (Incorrect, not reflexive)

(C) symmetric, but neither reflexive nor transitive (Correct)

(D) an equivalence relation (Incorrect, an equivalence relation must be reflexive, symmetric, and transitive)

✓Final answer

The relation RR is symmetric, but neither reflexive nor transitive, so the correct option is (C).

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