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Q.The degree of an objective function of a linear programming problem is 1
(A) 0
(B) 1
(C) 2
(D) Any natural number Assertion – Reason Based Questions Direction : Questions number 19 and 20 are Assertion and Reason based questions carrying 1 mark each. Two statements are given, one labelled Assertion (A) and other labelled Reason (R). Select the correct answer from the codes (A), (B), (C) and (D) as given below. (A) Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A). (B) Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A). (C) Assertion (A) is true and Reason (R) is false. (D) Assertion (A) is false and Reason (R) is true.

CBSECBSE Class XII Board 2026MCQ· 1mImportance★★★★★
✓ Free question

In linear programming, the objective function is always a linear expression, meaning each variable appears only to the first power. Therefore its degree is always 1, making option (B) the correct choice.

The question asks for the degree of the objective function in a linear programming problem. This is a concept check — it tests whether you understand what "linear" means in this context.

In linear programming, every constraint and the objective function must be linear. A linear expression in variables x1,x2,…,xnx_1, x_2, \dots, x_n has the form c1x1+c2x2+⋯+cnxn+dc_1 x_1 + c_2 x_2 + \dots + c_n x_n + d, where each cic_i and dd are constants. No variable is squared, cubed, or multiplied by another variable — the highest power of any variable is exactly 1.

So the degree of the objective function — the highest exponent of any variable in it — is always 1. That is the defining property of linearity.

Now let's walk through the reasoning step by step.

  1. Recall the definition of degree of a polynomial expression.

    The degree is the highest sum of exponents of variables in any term. For a single-variable term like 5x5x, the degree is 1. For 3x23x^2, it is 2. For a constant term like 77, the degree is 0.

  2. What form does an objective function take in LPP?

    It is always of the form Z=c1x1+c2x2+⋯+cnxnZ = c_1 x_1 + c_2 x_2 + \dots + c_n x_n, possibly plus a constant. Every term is a constant times a single variable to the first power. No term has xi2x_i^2, xixjx_i x_j, xi\sqrt{x_i}, or any nonlinearity.

  3. Therefore, the highest exponent on any variable is 1.

    Even if a constant term exists (degree 0), the overall degree of the expression is the maximum among its terms, which is 1.

  4. Why can't it be 0, 2, or any natural number?

    • Degree 0 would mean a constant objective — no variables at all. That is a trivial case but not the general definition; the objective function in LPP always involves variables to optimize.
    • Degree 2 or higher would make it a quadratic or higher-degree programming problem, which is not linear programming.
    • "Any natural number" is too broad — only degree 1 is allowed.
Watch out

A common mistake is to think the degree could be 0 because constants have degree 0. But the objective function must contain variables (otherwise there is nothing to optimize), so the degree is always 1.

Tip

If you ever see an objective like Z=5x+3y−2Z = 5x + 3y - 2, the degree is still 1 — the constant doesn't change the highest exponent. The "linear" in linear programming guarantees degree 1.

✓Final answer

The degree of the objective function of a linear programming problem is always 1, so the correct option is (B).

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