Skip to content
Question 25 of 61

Q.(m) Find the interquartile range and quartile deviation from the three quartiles 36, 54 and 72.

ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2019Subjective· 2mImportance★★★★★est
41% · 25/61 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Interquartile range =36= 36 and quartile deviation =18= 18.

Given the quartiles Q1=36Q_1 = 36, Q2=54Q_2 = 54, Q3=72Q_3 = 72.

Interquartile range:

I.Q.R.=Q3−Q1=72−36=36.I.Q.R. = Q_3 - Q_1 = 72 - 36 = 36.

Quartile deviation (semi-interquartile range):

Q.D.=Q3−Q12=362=18.Q.D. = \frac{Q_3 - Q_1}{2} = \frac{36}{2} = 18.

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.