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Question 43 of 61
Q.

Calculate the standard deviation from the following data :

x1020304050607080
y15305375100110115125
ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2022Subjective· 5mImportance★★★★★est
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σ=h∑fd2N−(∑fdN)2=104−0.380≈19.03\sigma=h\sqrt{\dfrac{\sum fd^2}{N}-\left(\dfrac{\sum fd}{N}\right)^2}=10\sqrt{4-0.380}\approx19.03.

Here xx is the variable and yy is its frequency ff. Use the step-deviation method with assumed mean A=50A=50 and class width h=10h=10, so d=x−5010d=\dfrac{x-50}{10}.

xxffddfdfdfd2fd^2
1015-4-60240
2030-3-90270
3053-2-106212
4075-1-7575
50100000
601101110110
701152230460
8012533751125
Total6233842492

So N=∑f=623N=\sum f=623, ∑fd=384\sum fd=384, ∑fd2=2492\sum fd^2=2492.

Apply the step-deviation standard-deviation formula: …

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