(a) From the following data find the mean deviation from its median: 10, 15, 18, 20, 30

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10, 15, 18, 20, 30

ChseodishaCHSE Odisha Plus Two (Class 12) Commerce Board 2019Subjective· 3mImportance★★★★★est

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Mean deviation about the median $= 5$ .

Step 1 — Median. Data $10, 15, 18, 20, 30$ is already in ascending order, $N = 5$ (odd), so median $=$ $\left(\dfrac{N+1}{2}\right)^{th} = 3^{rd}$ item $= 18$ .

Step 2 — Absolute deviations from the median $|x - 18|$ :

$x$	$\lvert x - 18\rvert$
10	8
15	3
18	0
20	2
30	12

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Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

CBSE 2022Set ANNUAL1 markMCQ
$Q. From the following the one which is a relative measure of dispersion is :$
(a) Range
(b) Quartile deviation
(c) Coefficient of mean deviation
(d) Standard deviation
›Reveal solutionSolution
Relative measures are ratios/coefficients; here that is the coefficient of mean deviation.

Measures of dispersion are of two kinds:

Absolute — expressed in the original units (Range, Quartile deviation, Mean deviation, Standard deviation).

Relative — a unit-free ratio obtained by dividing an absolute measure by an average (Coefficient of range, Coefficient of quartile deviation, Coefficient of mean deviation, Coefficient of variation). …
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CBSE 2022Set ANNUAL1 markMCQ
$Q. The mean deviation of 10, 12, 20 and 30, is :$
(a) $7$
(b) $18$
(c) $14$
(d) $6$
›Reveal solutionSolution

$\bar{x}=18$ , $\text{M.D.}=\frac{8+6+2+12}{4}=7$ .

Mean:

$\bar{x}=\frac{10+12+20+30}{4}=\frac{72}{4}=18.$

Absolute deviations from the mean:

$|10-18|=8,\;|12-18|=6,\;|20-18|=2,\;|30-18|=12.$

…

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CBSE 2022Set ANNUAL1 markMCQ
$Q. The formula for calculating coefficient of mean deviation is :$
(a) $\frac{\text{Mean}}{\text{Mean deviation}}$
(b) $\frac{\text{Mean deviation}}{\text{Mean}}$
(c) $\text{Mean deviation} \times \text{Mean}$
(d) $\frac{\text{Median}}{\text{Mean deviation}}$
›Reveal solutionSolution

Coefficient of M.D. $=\dfrac{\text{Mean deviation}}{\text{average used}}$ .

A relative measure of dispersion is formed by dividing the absolute measure by the corresponding average. For mean deviation taken about the mean,

$\text{Coefficient of M.D.}=\frac{\text{Mean deviation}}{\text{Mean}}.$

…

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Q.(a) From the following data find the mean deviation from its median: $10, 15, 18, 20, 30$

Concept understanding — Mean Deviation and its Coefficient

Q.(a) From the following data find the mean deviation from its median: 10,15,18,20,3010, 15, 18, 20, 3010,15,18,20,30

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Q.(a) From the following data find the mean deviation from its median: $10, 15, 18, 20, 30$

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