Phenol can be distinguished from ethanol by the reactions with ______. (Two or more than two options may be co

NCERT Exemplar · Q59

Q. Phenol can be distinguished from ethanol by the reactions with ____________. (Two or more than two options may be correct.)

(i)

Br_2

/water

(ii) Na

(iii) neutral

FeCl_3

(iv) all of these

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Concept understanding — Acidity Of Phenol

Inductive Effect on Acidity – From Intuition to Precision

Imagine you are holding a rope tied to a heavy box. If you pull the rope, the box moves toward you. Now imagine the rope is made of rubber bands — the pull still reaches the box, but it gets weaker the farther away you are. That is exactly how the inductive effect works inside a molecule.

The Core Intuition

An acid donates a proton ( $H^+$ ). After it does, the remaining part (the conjugate base) carries a negative charge. The stability of that negative charge determines how willing the molecule is to give up the proton. More stable conjugate base → stronger acid.

Now, some atoms or groups are electron-withdrawing — they pull electron density toward themselves through the sigma bonds. If such a group is attached near the acidic proton, it pulls some electron density away from the negative charge on the conjugate base. That spreads out (delocalises) the negative charge, making the conjugate base more stable. The acid becomes stronger.

Conversely, electron-donating groups push electron density toward the negative charge, concentrating it and making the conjugate base less stable. The acid becomes weaker.

Note

The inductive effect operates through sigma bonds only. It does not involve pi bonds or resonance. It is a permanent, through-bond polarisation.

The Precise Statement

Inductive effect on acidity: The acidity of a compound increases with the presence of electron-withdrawing groups (EWGs) near the acidic site, and decreases with electron-donating groups (EDGs). The effect is strongest when the group is closest to the acidic proton, and diminishes rapidly with distance.

Mathematically, for a series of substituted carboxylic acids:

\text{R-COOH} \quad \text{where R = substituent}

The acid dissociation constant $K_a$ changes as:

If R is electron-withdrawing (e.g., $-\text{Cl}$ , $-\text{NO}_2$ , $-\text{CF}_3$ ): $K_a$ increases → stronger acid.
If R is electron-donating (e.g., $-\text{CH}_3$ , $-\text{C}_2\text{H}_5$ ): $K_a$ decreases → weaker acid.

Why Distance Matters

The inductive effect falls off with distance because sigma bonds are localised. Each bond attenuates the effect by roughly a factor of 2–3. For example, compare:

Compound	$pK_a$	Explanation
$\text{CH}_3\text{COOH}$	4.76	Reference (no EWG)
$\text{ClCH}_2\text{COOH}$	2.86	Cl withdraws through one bond
$\text{Cl}_2\text{CHCOOH}$	1.29	Two Cl atoms, stronger withdrawal
$\text{Cl}_3\text{CCOOH}$	0.65	Three Cl atoms, strongest withdrawal
$\text{CH}_3\text{CH}_2\text{COOH}$	4.87	Ethyl group is electron-donating (slightly weaker acid)

Notice: $\text{ClCH}_2\text{COOH}$ is about 100 times stronger than acetic acid ( $\Delta pK_a \approx 1.9$ ). But if the Cl is moved further away:

Compound	$pK_a$
$\text{ClCH}_2\text{CH}_2\text{COOH}$	4.08
$\text{ClCH}_2\text{CH}_2\text{CH}_2\text{COOH}$	4.52

The effect fades as the chlorine moves farther from the carboxyl group. …

Why this formula?

Acidity of Phenol: Why It's More Acidic Than Alcohols

Let's build this from first principles — understanding why phenol is acidic is the key to mastering organic chemistry.

1. The Core Observation

Phenol ( $\ce{C6H5OH}$ ) has a pKa ≈ 10, while ethanol ( $\ce{CH3CH2OH}$ ) has a pKa ≈ 16.

This means phenol is about 1 million times more acidic than a typical alcohol.

The question: Why does the O–H bond in phenol break so much more easily?

2. The Key: Stability of the Conjugate Base

Acidity is determined by the stability of the conjugate base after losing $\ce{H+}$ .

Alcohol conjugate base: $\ce{CH3CH2O-}$ (alkoxide ion) — negative charge is localized on oxygen.
Phenol conjugate base: $\ce{C6H5O-}$ (phenoxide ion) — negative charge is delocalized into the benzene ring.

The Resonance Explanation

The phenoxide ion has multiple resonance structures:

\ce{C6H5O-} \leftrightarrow \text{(several resonance forms where negative charge moves to ortho/para carbons)}

Draw the structures mentally:

One structure has the negative charge on oxygen.
Other structures show the negative charge on carbon atoms at the ortho and para positions of the ring.

This delocalization spreads the negative charge over more atoms, making the ion more stable.

Key principle: The more stable the conjugate base, the stronger the acid.

3. Why Alcohols Can't Do This

In an alkoxide ion ( $\ce{RO-}$ ), the negative charge is stuck on oxygen.

There are no empty p-orbitals or conjugated $\pi$ systems nearby to accept the charge.

Result: The alkoxide is less stable, so the alcohol is less acidic.

4. The Inductive Effect Also Helps (But Resonance Dominates)

The benzene ring is slightly electron-withdrawing (due to its $sp^2$ carbons being more electronegative than $sp^3$ ).

This inductive effect pulls electron density away from the O–H bond, making the proton slightly more positive and easier to remove.

However, resonance stabilization of the conjugate base is the dominant factor — inductive effects alone cannot explain the million-fold difference.

5. The Quantitative Picture (pKa Values)

Compound	pKa	Conjugate base stability
Ethanol	~16	Localized charge on O
Phenol	~10	Delocalized charge via resonance
Acetic acid	~4.76	Even more resonance (two O atoms)

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Phenol and ethanol differ in acidity and aromatic reactivity. Phenol reacts with bromine water (electrophilic substitution) and neutral FeCl3 (colour complex); both react with Na (acidic H). So the correct options are (i) and (iii).

Reasoning

Option (i), Br2/water: phenol's activated aromatic ring undergoes rapid electrophilic substitution with bromine water at room temperature, giving a white precipitate of 2,4,6-tribromophenol. Ethanol has no aromatic ring and does not react. This distinguishes them - correct. …

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Here are the common mistakes students make on this question, along with how to avoid each.

Mistake 1: Forgetting that Na reacts with both phenol and ethanol

Many students see "Na" and immediately think of the classic phenol reaction (evolution of $H_2$ gas). They forget that ethanol also has a labile $-OH$ hydrogen and reacts with sodium to produce hydrogen gas.

The Trap: Option (B) Na is a distinguishing test only if you are looking for a difference in vigour (phenol reacts slower due to weaker acidity in practice, but both still react). In a multiple-choice exam, "distinguishing" usually means one reacts and the other does not.
How to Avoid: Memorise the reactivity order: Na metal reacts with any compound having an acidic hydrogen (alcohols, phenols, carboxylic acids, water). If a question asks for a distinguishing test, Na is not a reliable choice because both give the same observation (bubbles of $H_2$ ).

Mistake 2: Confusing the $Br_2$ /water test with the $Br_2$ / $CCl_4$ test

Students often think bromine water tests only for unsaturation (alkenes/alkynes). They forget that phenol undergoes electrophilic substitution with bromine water, even at room temperature, to give a white precipitate of 2,4,6-tribromophenol.

The Trap: Ethanol does not react with $Br_2$ /water at all. Phenol does. So this is a valid distinguishing test.
How to Avoid: Remember the specific reagent: $Br_2$ /water (aqueous bromine) is a test for phenol (substitution). $Br_2$ in $CCl_4$ (non-polar) is a test for unsaturation (addition). Write this distinction in your notes.

Mistake 3: Thinking neutral $FeCl_3$ gives a colour with all alcohols

Neutral $FeCl_3$ is a specific test for enols (compounds with a $-OH$ group attached to an $sp^2$ hybridised carbon). Phenol is an enol; ethanol is not.

The Trap: Students assume any $-OH$ compound gives a colour. They forget that aliphatic alcohols (like ethanol) do not give a violet/blue colour with neutral $FeCl_3$ .
How to Avoid: Link the $FeCl_3$ test to aromatic -OH (phenols) and enolisable $\beta$ -diketones only. Ethanol gives no colour change.

Mistake 4: Selecting "all of these" without checking each option independently …

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Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

GSEB Higher Secondary Certificate (HSC) Examination 2026Set ANNUAL1 markMCQ
$Q. Mark the correct order of decreasing acid strength of the following compounds.$
(a) Phenol
(b) 4-Nitrophenol (NO2 para to OH)
(c) 3-Methoxyphenol (OCH3 meta to OH)
(d) 3-Nitrophenol (NO2 meta to OH)
(e) 4-Methoxyphenol (OCH3 para to OH)
(a)
(e) >
(d) >
(b) >
(a) >
(c)
(b)
(b) >
(d) >
(a) >
(c) >
(e)
(c)
(d) >
(e) >
(c) >
(b) >
(a)
(d)
(e) >
(d) >
(c) >
(b) > (a)
›Reveal solutionSolution
Acidity of a substituted phenol rises with electron-withdrawing substituents (which stabilise the phenoxide anion) and falls with electron-donating substituents (which destabilise it), with the effect strongest when the group is para/ortho (conjugated) to –OH.

When phenol loses H+ to form the phenoxide ion, the negative charge is delocalised onto the ring, especially onto the ortho and para carbons. A substituent's effect on acidity depends on how it interacts with that delocalised negative charge:

–NO2 (strongly electron-withdrawing) pulls electron density away, stabilising the anion and INCREASING acidity — most strongly when placed para/ortho (direct resonance with the developing negative charge), and to a smaller extent even at meta (inductive-only). So both nitrophenols are more acidic than plain phenol, with the para-nitrophenol (b) the strongest acid (full resonance stabilisation) ahead of meta-nitrophenol (d, inductive only). …
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GUJCET 2025Set 031 markMCQ
$CCl_{4}$
›Reveal solutionSolution
[!TLDR]

Azo coupling of phenol with a diazonium salt to give an orange dye needs a mildly alkaline (phenoxide) medium.

Concept

Diazonium salts act as weak electrophiles and couple with electron-rich aromatics. Phenol couples best when converted to the phenoxide ion, which forms in an alkaline medium and is strongly activating toward electrophilic substitution.

Solution

$C_6H_5N_2^+Cl^- + C_6H_5OH \xrightarrow{\text{mild alkali}} p\text{-hydroxyazobenzene (orange dye)}$ . …
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GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQ
$Q. Which one of the following has the highest pKa value?$
(a) m - Nitro phenol
(b) p - Nitro phenol
(c) o - Cresol
(d) Phenol
›Reveal solutionSolution
Electron-withdrawing nitro groups increase phenol's acidity (lower pKa); the electron-donating methyl group of cresol decreases acidity (higher pKa) relative to phenol.

Acidity of substituted phenols is governed by how the substituent affects stabilisation of the phenoxide ion after loss of the acidic -OH proton:

Nitro (-NO2) is strongly electron-withdrawing (by both induction and resonance, especially at ortho/para), which stabilises the phenoxide anion and increases acidity (lowers pKa). Both m-nitrophenol and p-nitrophenol are therefore more acidic (lower pKa) than plain phenol. …
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GUJCET 2024Set 131 markMCQ
$Q. Arrange the following compounds in decreasing order of their acidic strength:$
(i) phenol;
(ii) 4-nitrophenol (para-NO2 phenol);
(iii) 4-methylphenol (para-cresol). (A)
(ii) >
(iii) >
(i) (B)
(iii) >
(i) >
(ii) (C)
(i) >
(ii) >
(iii) (D)
(ii) >
(i) > (iii)
›Reveal solutionSolution
Electron-withdrawing $-NO_2$ raises acidity; electron-donating $-CH_3$ lowers it.

Concept. Phenol acidity increases when the ring bears electron-withdrawing groups (stabilise the phenoxide) and decreases with electron-donating groups.

4-nitrophenol: $-NO_2$ (EWG) → most acidic. …
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GSEB Higher Secondary Certificate (HSC) Examination 2023Set ANNUAL1 markMCQ
$Q. Which compound has highest value of pKa?$
(a) m-nitrophenol
(b) phenol
(c) p-cresol
(d) o-nitrophenol
›Reveal solutionSolution
Highest pKa = weakest acid = p-cresol (methyl is electron-donating, destabilises the phenoxide).

Acidity of a phenol increases when electron-withdrawing groups (like -NO2) stabilise the phenoxide anion, and decreases with electron-donating groups (like -CH3).

m-nitrophenol, o-nitrophenol: -NO2 withdraws electrons -> more acidic -> low pKa. …
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GUJCET 2022Set 171 markMCQ
$Q. Which method is used to prepare salicylic acid from phenol? (A) Stephen reaction (B) Kolbe's reaction (C) Etard reaction (D) Reimer-Tiemann reaction$
›Reveal solutionSolution
Phenol → salicylic acid via Kolbe's reaction.

Concept. Sodium phenoxide reacts with CO $_2$ under pressure (Kolbe–Schmitt reaction); ortho-carboxylation followed by acidification gives salicylic acid (2-hydroxybenzoic acid).

Stephen reaction → aldehyde from nitrile. …
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GUJCET 2015Set C1 markMCQ
$Q. Which of the following acid does not have -COOH group? (A) Picric acid (B) Ethanoic acid (C) Benzoic acid (D) Salicylic acid$
›Reveal solutionSolution
[!TLDR] Picric acid (2,4,6-trinitrophenol) has no carboxyl group; its acidity is from an –OH made strongly acidic by three –NO $_2$ groups.

Concept

A carboxylic acid contains the –COOH functional group. Some acidic organic compounds are acidic without a –COOH — for example, nitro-substituted phenols, where electron-withdrawing groups stabilise the phenoxide and make the phenolic –OH strongly acidic.

Solution

Picric acid = 2,4,6-trinitrophenol: acidic –OH (phenolic), no –COOH. …
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GUJCET 2015Set C1 markMCQ
$Q. Which of the following statement is not correct? (A) Phenol is neutralised by sodium carbonate (B) Phenol is used to prepare analgesic drugs (C) Solubility of phenol in water is more than that of chlorobenzene (D) Boiling point of o-nitrophenol is lower than that of p-nitrophenol$
›Reveal solutionSolution
[!TLDR] Phenol is too weak an acid to be neutralised by sodium carbonate, so statement (A) is not correct.

Concept

Acidity ordering: carboxylic acid > carbonic acid > phenol. A compound reacts with (is neutralised by) a carbonate only if it is a stronger acid than carbonic acid. Phenol is weaker than carbonic acid, so it does not liberate CO $_2$ from Na $_2$ CO $_3$ or NaHCO $_3$ ; it does, however, react with the stronger base NaOH to give sodium phenoxide.

Solution

(A) 'Phenol is neutralised by sodium carbonate' — incorrect; phenol is too weak an acid. ✗ (this is the answer)

(B) Phenol is used to make analgesic drugs (e.g. aspirin/paracetamol routes) — correct. …
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←Previous questionQ58 — Which of the following reagents can be used to oxidise primary alcohol…→Next questionQ60 — Which of the following compounds are benzylic alcohols? (Two or more o…

Q.Phenol can be distinguished from ethanol by the reactions with ____________. (Two or more than two options may be correct.)

Concept understanding — Acidity Of Phenol

Inductive Effect on Acidity – From Intuition to Precision

The Core Intuition

The Precise Statement

Why Distance Matters

Why this formula?

Acidity of Phenol: Why It's More Acidic Than Alcohols

1. The Core Observation

2. The Key: Stability of the Conjugate Base

The Resonance Explanation

3. Why Alcohols Can't Do This

4. The Inductive Effect Also Helps (But Resonance Dominates)

5. The Quantitative Picture (pKa Values)

Reasoning

Method: Reagent-Based Distinction Test for Phenol vs. Ethanol

Steps:

Mistake 1: Forgetting that Na reacts with both phenol and ethanol

Mistake 2: Confusing the $Br_2$ /water test with the $Br_2$ / $CCl_4$ test

Mistake 3: Thinking neutral $FeCl_3$ gives a colour with all alcohols

Mistake 4: Selecting "all of these" without checking each option independently …

Concept

Solution

Concept

Solution

Concept

Solution

Q.Phenol can be distinguished from ethanol by the reactions with ____________. (Two or more than two options may be correct.)

Reasoning

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