Q.Match the structures of the compounds given in Column I with the names of the compounds given in Column II. (In the Exemplar the Column I entries are drawn structures; their carriable names are given inline below.)
Column I:
Column II:
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — IUPAC Nomenclature
IUPAC Nomenclature (Organic Compounds)
IUPAC nomenclature is a systematic way to name a compound so that its name alone tells you its exact structure, with no ambiguity. Every organic name follows the same underlying recipe, whatever the functional group.
The Recipe
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Identify the principal characteristic group. If the molecule has a functional group senior enough to be named as a suffix (carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine, and so on down the seniority order), that group decides the suffix and must be included in the parent chain. A halogen is never senior enough to be a suffix — it is always named as a prefix ("halo-"), whatever else is present.
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Choose the parent chain. The parent is the longest continuous carbon chain that contains the principal characteristic group (if there is one). Among chains of the same length, the one with the most substituents wins.
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Number the chain. Number from whichever end gives the LOWEST LOCANT to the principal characteristic group first. If there is no principal group (e.g. a simple haloalkane, or an alkene with a halogen substituent), lowest locant goes to the site of unsaturation (double/triple bond) first, then to substituents as a set.
Watch outWhen two numbering directions give the SAME locant for the principal group/unsaturation (a genuine tie), the tie-break is the lowest locant SET for the substituents as a group — compare the two sets at their first point of difference. Only if the sets are themselves tied does the alphabetically-first substituent get the lower number.
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Name and cite the substituents as prefixes, in alphabetical order (ignoring multiplying prefixes like di-/tri- but not ignoring structural prefixes like iso-/cyclo-), each with its own locant.
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Assemble the name: locants + substituent prefixes (alphabetical) + parent chain name + suffix (if any).
Worked Example
CH3−CH(Cl)−CH(CH3)−CH2−CH3: the longest chain is 5 carbons (pentane), no principal characteristic group (just a halogen substituent), so number for the lowest locant set. From the left: Cl at C2, methyl at C3 → set {2,3}. From the right: methyl at C3, Cl at C4 → set {3,4}. {2,3} is lower, so numbering from the left wins: 2-chloro-3-methylpentane. …
Why this formula?
IUPAC Nomenclature: Why the Rules Work the Way They Do
IUPAC nomenclature is not a single formula, but a system of rules designed to give every organic compound a unique, unambiguous name. The "why" behind these rules lies in clarity, consistency, and communication — ensuring that a chemist in Tokyo and one in Toronto draw the same structure from the same name.
1. The Core Principle: The Longest Carbon Chain
Rule: Identify the longest continuous chain of carbon atoms. This becomes the parent chain (e.g., pentane, hexane).
Why?
- The longest chain represents the backbone of the molecule.
- It gives the most stable, fundamental name — shorter chains would be branches, not the main structure.
- Example: In a molecule with 5 carbons in a row and a 2-carbon branch, calling it "pentane" (not "ethane") tells you the core skeleton is 5 carbons long.
Key idea: The parent chain is the maximum continuous path — not necessarily the one that looks "straight" on paper.
2. Numbering: Lowest Locants (The "First Point of Difference" Rule)
Rule: Number the parent chain so that substituents get the smallest possible numbers. When there's a tie, compare the first point of difference.
Why?
- This ensures reproducibility — two chemists will always number the same way.
- It avoids ambiguity: "2-methylpentane" is unambiguous; "3-methylpentane" would be a different compound.
- The first point of difference rule: If you have substituents at positions 2,4 and 3,5, choose 2,4 because 2 < 3 (the first number is smaller).
Example:
- For a methyl group on carbon 2 vs. carbon 4 of a 5-carbon chain:
- 2-methylpentane (correct)
- 4-methylpentane (wrong — higher number)
3. Alphabetical Order of Substituents
Rule: List substituents in alphabetical order (ignoring prefixes like di-, tri-, sec-, tert- but not iso-).
Why?
- Alphabetical order is a universal sorting convention — no need to remember priority based on size or complexity.
- It makes names searchable and predictable.
- Example: "3-ethyl-2-methylpentane" (e before m) — not "2-methyl-3-ethylpentane".
Exception: Prefixes like iso- and neo- are considered part of the name (e.g., isopropyl comes before methyl because "i" < "m").
4. Multiple Bonds: The "Lowest Locant" Rule for Alkenes/Alkynes
Rule: Number the chain so that the double or triple bond gets the lowest possible number, even if it means giving a substituent a higher number.
Why?
- The functional group (alkene/alkyne) is more important than alkyl substituents.
- The bond position defines the compound's reactivity and geometry.
- Example: In pent-2-ene (not pent-3-ene), the double bond is between carbons 2 and 3 — the lower number (2) is used.
Priority order:
- Principal functional group (e.g., -OH, -COOH, C=C)
- Multiple bonds
- Substituents (alkyl, halo, etc.)
5. The "Suffix" and "Prefix" System …
The key idea is that common names (like cresol, anisole) correspond to specific IUPAC systematic names based on the substitution pattern on the benzene ring.
Step 1 – Identify the functional group and substituents for each common name.
- o-cresol = 2-methylphenol (methyl at ortho position to –OH).
- catechol = 1,2-dihydroxybenzene (two –OH groups adjacent).
- resorcinol = 1,3-dihydroxybenzene (two –OH groups meta).
- hydroquinone = 1,4-dihydroxybenzene (two –OH groups para).
- anisole = methoxybenzene (–OCH₃).
- phenetole = ethoxybenzene (–OC₂H₅).
Step 2 – Match each Column I entry to its correct IUPAC name in Column II.
(i) o-cresol → (d) 2-methylphenol …
This is a matching problem between common names (Column I) and IUPAC/systematic names (Column II) of phenolic and ether compounds. The key is to identify the functional groups and substituent positions: o-cresol = 2-methylphenol, catechol = 1,2-dihydroxybenzene, resorcinol = 1,3-dihydroxybenzene, hydroquinone = 1,4-dihydroxybenzene, anisole = methoxybenzene, phenetole = ethoxybenzene.
The question tests your ability to translate between the traditional common names still used in organic chemistry and the systematic IUPAC nomenclature. Each compound in Column I is a well-known aromatic derivative. Let's go through them one by one.
1. o-cresol
The prefix o- (ortho) means the two substituents are adjacent on the benzene ring. Cresol is the common name for methylphenol. So o-cresol is 2-methylphenol — a methyl group at position 1 and a hydroxyl group at position 2 (or vice versa; the hydroxyl gets priority in numbering). This matches option (d).
2. catechol
Catechol is the traditional name for benzene-1,2-diol — two hydroxyl groups on adjacent carbons. The IUPAC name is 1,2-dihydroxybenzene. That's option (c).
3. resorcinol
Resorcinol is benzene-1,3-diol — hydroxyl groups at positions 1 and 3. The systematic name is 1,3-dihydroxybenzene, which is option (f).
4. hydroquinone
Hydroquinone is benzene-1,4-diol — hydroxyl groups opposite each other. The IUPAC name is 1,4-dihydroxybenzene, option (a).
5. anisole
Anisole is the common name for methoxybenzene — a benzene ring with a methoxy (−OCH3) substituent. That's option (e).
6. phenetole
Phenetole is the common name for ethoxybenzene — a benzene ring with an ethoxy (−OC2H5) group. That's option (b). …
Method: IUPAC Name-to-Structure Matching by Functional Group & Substituent Position
This method uses the IUPAC systematic name to identify the parent ring, functional groups, and substituent positions, then matches it to the common name.
Steps
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Identify the parent ring
All compounds in Column II contain a benzene ring (phenol derivatives or ethers).
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Locate the principal functional group
- -ol → phenol (hydroxy group, –OH)
- -oxybenzene → ether (alkoxy group, –OR)
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Count and number substituent positions
- For dihydroxybenzenes: numbers indicate –OH positions (1,2-; 1,3-; 1,4-).
- For methylphenol: methyl is at position 2 (ortho).
- For alkoxybenzenes: ethoxy = –OCH₂CH₃, methoxy = –OCH₃.
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Match to common names
Use the standard common names for these well-known compounds.
Matching Table
| Column I (Common Name) | Column II (IUPAC Name) | Reason |
|---|---|---|
| (i) o-cresol | (d) 2-methylphenol | o- = ortho = position 2; methyl + phenol |
| (ii) catechol | (c) 1,2-dihydroxybenzene | Two –OH groups at positions 1 and 2 |
| (iii) resorcinol | (f) 1,3-dihydroxybenzene | Two –OH groups at positions 1 and 3 |
Here are the most common mistakes students make when matching these structures with their IUPAC names, along with how to avoid each.
Mistake 1: Confusing the Positions of the Hydroxyl Groups
This is the most frequent error. Students mix up the three dihydroxybenzene isomers: catechol (1,2-), resorcinol (1,3-), and hydroquinone (1,4-).
- The Mistake: Matching catechol with 1,3-dihydroxybenzene or resorcinol with 1,4-dihydroxybenzene.
- How to Avoid:
- Visualize the "Ortho, Meta, Para" rule. The common names directly hint at the relative positions.
- Catechol = ortho (1,2-). Think "C" for "Close" or "C" for "ortho" (the first vowel is 'o').
- Resorcinol = meta (1,3-). Think "R" for "Remote" or "R" for "meta" (the vowel is 'e').
- Hydroquinone = para (1,4-). Think "H" for "Hydrogen" or "H" for "para" (the vowel is 'a').
- Draw it out. If you are unsure, quickly sketch the benzene ring and place the two
-OHgroups at the 1,2-, 1,3-, and 1,4- positions. The pattern is:- 1,2- → Catechol
- 1,3- → Resorcinol
- 1,4- → Hydroquinone
- Visualize the "Ortho, Meta, Para" rule. The common names directly hint at the relative positions.
Mistake 2: Misidentifying the Parent Chain in Cresol
Students often forget that the methyl group is the substituent on the phenol ring, not the other way around.
- The Mistake: Matching o-cresol with 1-methyl-2-hydroxybenzene or similar, instead of 2-methylphenol.
- How to Avoid:
- Remember the priority rule: The
-OHgroup (phenol) is the parent functional group. The methyl group is a substituent. - The name "cresol" implies a methylphenol. The "o-" (ortho) tells you the methyl is at the 2-position relative to the
-OH. - Correct IUPAC name: 2-methylphenol (not 1-hydroxy-2-methylbenzene, though that is also acceptable, the standard is to name it as a substituted phenol).
- Remember the priority rule: The
Mistake 3: Confusing Anisole and Phenetole
These are both ethers, but students mix up the alkyl group attached to the oxygen.
- The Mistake: Matching anisole with ethoxybenzene or phenetole with methoxybenzene.
- How to Avoid:
- Focus on the alkyl group's name.
- Anisole = Methyl phenyl ether. The IUPAC name is methoxybenzene.
- Phenetole = Ethyl phenyl ether. The IUPAC name is ethoxybenzene.
- Mnemonic: "Anisole" sounds like "An-isole" → "An-is" → "An-is" → "M-ethyl"? No. Better: "Anisole" has an 'A' for "Alkyl" but the alkyl is methyl. "Phenetole" has an 'E' for "Ethyl". Think: Anisole = Methyl; Phenetole = Ethyl.
- Focus on the alkyl group's name.
Mistake 4: Forgetting the "1-methoxy-4-methylbenzene" Distractor
This is a trick. It looks like anisole but has an extra methyl group.
- The Mistake: Matching anisole with 1-methoxy-4-methylbenzene.
- How to Avoid:
- Read the name carefully. "1-methoxy-4-methylbenzene" has two substituents: a methoxy group and a methyl group. Anisole (methoxybenzene) has only one substituent (the methoxy group). …
- GSEB Higher Secondary Certificate (HSC) Examination 2026Set ANNUAL1 markMCQQ.How many H and O atoms are present in vanillin respectively?(a) 8 and 4(b) 9 and 3(c) 9 and 4(d) 8 and 3
›Reveal solutionSolution
Vanillin's molecular formula is C8H8O3 (4-hydroxy-3-methoxybenzaldehyde), giving 8 H atoms and 3 O atoms.
Vanillin, a naturally occurring aromatic aldehyde (the primary flavour compound of vanilla), has the structure of a benzene ring bearing three substituents: –CHO (aldehyde), –OH (hydroxyl), and –OCH3 (methoxy), with 3 remaining ring hydrogens.
Its molecular formula is C8H8O3: …
- GUJCET 2025Set 031 markMCQQ.Identify the functional group present in Vanillin. (A) −COOH,−OH,−OC2H5 (B) −CHO,−OH,−OCH3 (C) −COOH,−CH3,−OCH3 (D) −CHO,−OH,−OC2H5
›Reveal solutionSolution
[!TLDR]
Vanillin contains −CHO, −OH and −OCH3 groups.
Concept
Vanillin is the aromatic aldehyde 4-hydroxy-3-methoxybenzaldehyde, responsible for the smell of vanilla.
Solution
Its structure is a benzene ring bearing:
- an aldehyde group −CHO,
- a phenolic hydroxyl group −OH, …
- GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQQ.Which one is the correct IUPAC name of Phenyl isopentyl ether.(a) 3 - Methyl butoxy benzene(b) 2 - Methyl butoxy benzene(c) 4 - Phenoxy 2-Methyl butane(d) 1 - Phenoxy - 3 - Methyl butane
›Reveal solutionSolution
Phenyl isopentyl ether is C6H5-O-CH2CH2CH(CH3)2; naming the isopentyl (3-methylbutyl) chain as the substituent alkoxy group on benzene gives 3-methylbutoxybenzene.
Isopentyl (isoamyl) group = 3-methylbutyl = -CH2-CH2-CH(CH3)-CH3 (numbering the 4-carbon chain from the point of attachment, with a methyl branch at C3).
Phenyl isopentyl ether: C6H5-O-CH2-CH2-CH(CH3)-CH3
…
- GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQQ.What is number of Hydrogen atom in Cinnamaldehyde?(a) 8(b) 9(c) 7(d) 5
›Reveal solutionSolution
Cinnamaldehyde is C6H5-CH=CH-CHO (molecular formula C9H8O); counting hydrogens on the phenyl ring, the vinyl carbons, and the aldehyde group gives 8 in total.
Cinnamaldehyde structure: C6H5-CH=CH-CHO (3-phenylprop-2-enal)
Count hydrogens:
- Phenyl ring (C6H5-): 5 H
- =CH-CH= (the two vinylic carbons): 1 H each = 2 H …
- GSEB Higher Secondary Certificate (HSC) Examination 2024Set ANNUAL1 markMCQQ.Name the following compound according to IUPAC system: (CH3)2-CH-CH2-CH(OH)-CH-(CH2OH)-CH3(a) 2,5-dimethyl-Hexane-1,3-diol(b) 2-methyl-4-Hydroxy-5-(methyl alcohol) Hexane(c) 2,5 dimethyl-Hexane-4,6-diol(d) 5 methyl-3-Hydroxy-(methyl alcohol) Hexane
›Reveal solutionSolution
Naming this compound needs choosing the longest carbon chain that includes BOTH hydroxyl-bearing carbons (since -diol suffix groups must be part of the principal chain), then numbering to give the OH groups the lowest locants.
Structure: (CH3)2CH-CH2-CH(OH)-CH(CH2OH)-CH3
The two -OH groups are on: the middle CH(OH) carbon, and the terminal -CH2OH carbon (attached as a branch off the next carbon). To include both in the main chain (required since they are the principal characteristic group, -diol), trace a 6-carbon path: start at the CH2OH carbon (C1), through the carbon bearing it (C2, which also carries a -CH3 branch), through the CH-OH carbon (C3), the CH2 (C4), the CH bearing the remaini …
- GSEB Higher Secondary Certificate (HSC) Examination 2023Set ANNUAL1 markMCQQ.Which compound will give yellow precipitate on reaction with sodium hypoiodite?(a) sec-Butyl alcohol(b) tert-Butyl alcohol(c) isobutyl alcohol(d) n-Butyl alcohol
›Reveal solutionSolution
The iodoform test (yellow CHI3) is positive for CH3-CH(OH)- alcohols; sec-butyl alcohol fits.
Sodium hypoiodite (NaOI = NaOH + I2) gives a yellow precipitate of iodoform (CHI3) with compounds containing the CH3-CO- group or an alcohol that oxidises to it, i.e. the CH3-CH(OH)- unit. …
- GSEB Higher Secondary Certificate (HSC) Examination 2022Set ANNUAL1 markMCQQ.What is the correct structural formula of cinnamaldehyde?(a) Ph-CH=CH-CHO(b) Ph-CH2-CH2-CHO(c) Ph-C#C-CHO(d) Ph-CH2-CH=CH-CHO
›Reveal solutionSolution
Cinnamaldehyde is the alpha,beta-unsaturated aldehyde responsible for cinnamon's flavour/aroma, with a phenyl group conjugated through a C=C double bond to the aldehyde.
Its structure is Ph-CH=CH-CHO (3-phenylprop-2-enal): a benzene ring attached to a -CH=CH-CHO chain, giving full conjugation between the ring, the alkene, and the carbonyl. Option (b) is the saturated (dihydro) analogue, option (c) has a triple bond in …
- GUJCET 2021Set 151 markMCQQ.From following, IUPAC name of compound [FIGURE: cyclohexane ring bearing two CH3 groups (gem-dimethyl) on one carbon and an OC2H5 (ethoxy) group on the adjacent carbon] is? (A) 2-ethoxy-1,1-dimethyl cyclohexane (B) 5-ethoxy-6,6-dimethyl cyclohexane (C) 1-ethoxy-2,2-dimethyl cyclohexane (D) 1-ethoxy-6,6-dimethyl cyclohexane
›Reveal solutionSolution
Lowest-locant rule fixes the gem-dimethyl carbon as C-1, giving 2-ethoxy-1,1-dimethylcyclohexane.
Concept — lowest locants. The substituents are one ethoxy and two methyl groups, on two adjacent ring carbons. Compare the two possible numbering directions:
- gem-dimethyl carbon = C1, ethoxy carbon = C2 → locant set {1,1,2}
- ethoxy carbon = C1, gem-dimethyl carbon = C2 → locant set {1,2,2} …
- GUJCET 2019Set 131 markMCQQ.Give the IUPAC name for methyl salicylate. (A) Methyl - 3 - hydroxy benzoate (B) Methyl - 2 - hydroxy benzoate (C) 2' - hydroxy benzoic acid (D) Methoxy benzoic acid
›Reveal solutionSolution
Methyl salicylate is the methyl ester of salicylic acid (2-hydroxybenzoic acid): methyl 2-hydroxybenzoate.
Concept — naming an ester. Salicylic acid is 2-hydroxybenzoic acid (OH ortho to COOH). Its methyl ester replaces the acid –OH with –OCH₃, giving methyl 2-hydroxybenzoate. …
- GSEB Higher Secondary Certificate (HSC) Examination 2018Set ANNUAL1 markMCQQ.What is the IUPAC name of 'Acrolein'?(a) Pentanal(b) 3-methoxy propanal(c) But-2-enal(d) Prop-2-enal
›Reveal solutionSolution
Acrolein = CH2=CH-CHO = prop-2-enal.
Acrolein (acrylaldehyde) has the structure CH2=CH-CHO: a three-carbon chain with an aldehyde group (C1) and a double bond between C2 and C3. …
- GUJCET 2015Set C1 markMCQQ.What is IUPAC name for isophthalic acid? (A) Benzene-1,2 dicarboxylic acid (B) Benzene-1,3 dicarboxylic acid (C) Benzene-1,4 dicarboxylic acid (D) Benzene-1,5 dicarboxylic acid
›Reveal solutionSolution
[!TLDR]
Isophthalic acid = benzene-1,3-dicarboxylic acid.
Concept
The three benzene dicarboxylic acids: phthalic acid = benzene-1,2- (ortho), isophthalic acid = benzene-1,3- (meta), terephthalic acid = benzene-1,4- (para).
Solution …
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