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Worked Examples · Example 8

Q.Find the modulus and the principal argument of z=−1+iz=-1+i, and express it in polar form.

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Here a=−1, b=1a=-1,\ b=1.

Modulus:

r=(−1)2+12=1+1=2.r=\sqrt{(-1)^{2}+1^{2}}=\sqrt{1+1}=\sqrt2.

Argument: the point (−1,1)(-1,1) has a<0, b>0a<0,\ b>0, so it lies in Quadrant II. The reference angle is

α=tan⁡−1∣ba∣=tan⁡−1 ⁣∣1−1∣=tan⁡−11=π4,\alpha=\tan^{-1}\left|\frac{b}{a}\right|=\tan^{-1}\!\left|\frac{1}{-1}\right|=\tan^{-1}1=\frac{\pi}{4},

and in Quadrant II the principal argument is

θ=π−α=π−π4=3π4.\theta=\pi-\alpha=\pi-\frac{\pi}{4}=\frac{3\pi}{4}.

Polar form:

z=2(cos⁡3π4+isin⁡3π4).z=\sqrt2\left(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4}\right). …

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