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Answer the following · Q15

Q.Why the second ionization enthalpy is greater than the first ionization enthalpy?

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Step 1. Recall the two processes. ΔiH1\Delta_iH_1: X(g)→X+(g)+e−X(g)\rightarrow X^+(g)+e^- (removing an electron from a neutral atom). ΔiH2\Delta_iH_2: X+(g)→X2+(g)+e−X^+(g)\rightarrow X^{2+}(g)+e^- (removing a further electron from the already-positive cation formed in the first step).

Step 2. Compare the starting species. X+X^+ has the same nuclear charge as XX but one fewer electron — so the remaining electrons in X+X^+ experience less electron-electron repulsion (less shielding) and hence a LARGER effective nuclear charge than they did in the neutral atom.

Step 3. Draw the conclusion. Because the electron being removed in the second ionization is held more tightly (by this larger effective nuclear charge) than any electron in the neutral atom was, MORE energy must be supplied to remove it. …

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