Q.Which of the following is true for 2 moles of an ideal gas ? a. PV = nRT b. PV = RT c. PV = 2RT d. PV = T
Concept understanding — Ideal Gas Equation
The Intuition: What Does an "Ideal Gas" Even Mean?
Imagine a box full of tiny, perfectly bouncy balls — millions of them — zipping around in straight lines, never sticking to each other or to the walls. They take up no space themselves (their own volume is zero), and when they collide, they don't lose any energy. That's an ideal gas: a model where the only thing that matters is the motion of the particles.
Real gases (like air, oxygen, or helium) behave almost like this at low pressures and high temperatures. The ideal gas is a simplification that lets us predict how a gas will respond when we squeeze it, heat it, or add more of it.
The Three Laws That Came Before
Before the full equation, scientists discovered three separate patterns:
Boyle's Law — If you keep the temperature and amount of gas fixed, squeezing the gas into a smaller volume makes the pressure go up. Double the pressure, half the volume. Mathematically: P∝V1 (at constant n and T).
Charles's Law — If you keep the pressure and amount fixed, heating the gas makes it expand. Double the absolute temperature (in Kelvin), double the volume. So: V∝T (at constant n and P).
Avogadro's Law — If you keep pressure and temperature fixed, doubling the number of gas particles doubles the volume. So: V∝n (at constant P and T).
Each law holds a different variable constant. The genius move was to combine all three into one statement.
The Combined Statement: The Ideal Gas Equation
Putting the three proportionalities together:
V∝PnT
Remove the proportionality sign by introducing a constant R (the universal gas constant):
V=PnRT
Or, more familiarly:
PV=nRT
PV=nRT
That's it. One equation that tells you everything about the state of an ideal gas.
What Each Symbol Means
- P — Pressure of the gas (usually in pascals, Pa, or atmospheres, atm)
- V — Volume the gas occupies (in cubic metres, m³, or litres, L)
- n — Number of moles of gas (not number of molecules — one mole is 6.022×1023 particles)
- R — Universal gas constant. Its value depends on the units you use. The two you'll see most often:
- R=8.314J mol−1K−1 (when using SI units: Pa, m³)
- R=0.0821L atm mol−1K−1 (when using L and atm)
- T — Absolute temperature, always in kelvin (K). Never in Celsius. To convert: T(K)=T(°C)+273.15
Temperature must always be in kelvin. Using Celsius will give you a completely wrong answer — the equation is built on absolute zero as the starting point.
Why This Equation Is So Powerful
If you know any four of the five quantities (P, V, n, T, R), you can find the fifth. That means you can:
- Find how much gas is in a container by measuring pressure, volume, and temperature.
- Predict what happens to pressure when you heat a sealed can.
- Calculate the volume a gas will occupy at a different temperature and pressure.
A Simple Example
A 2.0 L container holds 0.50 moles of oxygen gas at 300 K. What is the pressure inside?
Use PV=nRT with R=0.0821L atm mol−1K−1:
P×2.0=0.50×0.0821×300
P=2.00.50×0.0821×300
P=6.16atm
Always check your units match the value of R you're using. If volume is in litres and pressure in atm, use R=0.0821. If volume is in m³ and pressure in Pa, use R=8.314.
The Big Picture
The ideal gas equation is not a law of nature — it's a model. It works beautifully for most gases under everyday conditions (room temperature, atmospheric pressure). It fails when gases are very cold (particles start sticking) or under very high pressure (particles get too close and their own volume matters). But for your exams and for building intuition, it's the single most important equation in gas behaviour.
The ideal gas equation PV = nRT is one of the most tested formulas in the NCERT/CBSE Class 11 Chemistry syllabus, and "ideal gas equation numericals class 11 chemistry" is among the highest-searched revision topics for this unit. It's also a near-guaranteed important-question type in JEE Main and NEET, often combined with molar mass or density calculations.
The ideal gas equation PV = nRT holds for any number of moles, including n = 2.
a. PV = nRT
Step 1. The ideal gas equation PV = nRT is the GENERAL relationship that holds for any amount of gas, whatever the number of moles n happens to be.
Step 2. For 2 moles specifically, substituting n = 2 into PV = nRT does give PV = 2RT, so option (c) is also numerically consistent for this particular case -- but it is just a special case of the general equation, not itself the fundamental law.
Step 3. Option (b), PV = RT, is only correct for exactly 1 mole (n = 1), and option (d), PV = T, omits R and n entirely and is dimensionally wrong.
Step 4. The safest, most general and universally correct statement of the ideal gas law for ANY amount of gas, including 2 moles, is PV = nRT.
a. PV = nRT
Recognise that PV = nRT is the general form valid for every value of n; substituting a specific n merely gives one of its special cases.
- Picking PV = RT (the n = 1 special case) by forgetting that n changes when the mole count changes.
- Not recognising that PV = 2RT is a valid but narrower restatement of the same general law for n = 2.
- CBSE 2026Set ANNUAL1 markMCQQ.The value of gas constant in equation of state for an ideal gas PV = nRT depends upon(a) Nature of the gas(b) Pressure of the gas(c) Temperature of the gas(d) Unit of measurement
›Reveal solutionSolution
The gas constant R depends only on the units of measurement.
R is a universal (same for every gas) constant. It does not depend on the nature, pressure or temperature of the gas. Its numerical value merely changes with the chosen units: R = 0.0821 L·atm·mol⁻¹·K⁻¹ = 8.314 J·mol⁻¹·K⁻¹ = 2 cal·mol⁻¹·K⁻¹.
✓Final answer(D) Unit of measurement.
- CBSE 2025Set ANNUAL1 markMCQQ.If Temperature and Volume of an ideal gas is increased to twice its values, the initial pressure P becomes :(a) P(b) 4 P(c) 3 P(d) 2 P
›Reveal solutionSolution
For a fixed amount of ideal gas, if both temperature and volume are doubled, the pressure stays unchanged: P' = P.
Start from the ideal gas law: PV = nRT, so P = nRT/V.
Let the initial pressure, volume and temperature be P, V, T (n and R are constants for a fixed amount of gas).
Now V' = 2V and T' = 2T. The new pressure is:
P' = nRT'/V' = nR(2T)/(2V) = nRT/V = P
The factor of 2 in the numerator (from T doubling) is exactly cancelled by the factor of 2 in the denominator (from V doubling), so the pressure comes back to its original value P. This makes physical sense: raising T alone would push the gas to expand or raise pressure, but here the volume is deliberately let out to exactly the extent that offsets the temperature rise.
✓Final answerThe correct option is (a) P — doubling both T and V leaves the pressure unchanged, since P' = nR(2T)/(2V) = nRT/V = P.
- CBSE 2024Set ANNUAL1 markMCQQ.The value of gas constant (R) in S.I. unit is(a) 8.31 × 10^7 erg K^-1 mol^-1(b) 8.31 J K^-1 mol^-1(c) 0.0821 litre atm K^-1 mol^-1(d) 2 cal K^-1 mol^-1
›Reveal solutionSolution
R = 8.31 J K⁻¹ mol⁻¹ in SI units.
The gas constant R can be expressed in different unit systems depending on the units of P and V used: 8.314 J K⁻¹ mol⁻¹ (SI, since J = Pa·m³), 0.0821 L·atm K⁻¹ mol⁻¹ (older practical units), 8.314 × 10⁷ erg K⁻¹ mol⁻¹ (CGS), and about 2 cal K⁻¹ mol⁻¹. In SI units (Pascal, cubic metre), R = 8.31 J K⁻¹ mol⁻¹.
✓Final answer(B) 8.31 J K⁻¹ mol⁻¹.
- CBSE 2023Set ANNUAL1 markMCQQ.The value of R in calorie is(a) 2 Cals k^-1 mol^-1(b) 4 Cals k^-1 mol^-1(c) 8 Cals k^-1 mol^-1(d) None of these
›Reveal solutionSolution
R is about 2 cal K-1 mol-1.
The universal gas constant R has the same physical value in different unit systems: 8.314 J K-1 mol-1 or 0.0821 L atm K-1 mol-1. Converting to calories (1 cal = 4.184 J), R = 8.314/4.184 = 1.987 cal K-1 mol-1, which is conventionally rounded to about 2 cal K-1 mol-1.
The gas constant appears throughout the NCERT/CBSE Class 11 Chemistry chapter States of Matter.
✓Final answer(a) 2 Cals k-1 mol-1.
- CBSE 2023Set ANNUAL1 markMCQQ.The ideal gas equation is expressed as :(a) PV = nR(b) PV = nRT(c) PV = nT(d) PV = T
›Reveal solutionSolution
The ideal gas equation is PV = nRT.
Combining Boyle's law (V ∝ 1/P), Charles's law (V ∝ T) and Avogadro's law (V ∝ n) gives V ∝ nT/P, i.e. PV = nRT, where R is the universal gas constant. This single equation describes the P-V-T behaviour of an ideal gas and is the starting point for gas-law calculations. The other options are dimensionally incomplete.
The ideal gas equation is central to the NCERT/CBSE Class 11 Chemistry chapter States of Matter.
✓Final answer(b) PV = nRT.
- CBSE 2022Set ANNUAL1 markMCQQ.7.5 g of a gas occupies a volume of 5.6 L at 0 degree C and 1 atm pressure. The gas is:(a) CO(b) NO(c) CO2(d) N2O
›Reveal solutionSolution
Using the molar volume at STP (22.4 L/mol), the moles of gas and hence its molar mass can be found; the calculated molar mass of 30 g/mol identifies the gas as NO.
Given: mass = 7.5 g, volume = 5.6 L at 0°C and 1 atm (STP).
Step 1: Find moles of gas using the molar volume at STP.
moles = volume / molar volume at STP = 5.6 L / 22.4 L/mol = 0.25 mol
Step 2: Find molar mass.
Molar mass = mass / moles = 7.5 g / 0.25 mol = 30 g/mol
Step 3: Match to the options.
- CO: 12 + 16 = 28 g/mol
- NO: 14 + 16 = 30 g/mol ✓
- CO2: 12 + 32 = 44 g/mol
- N2O: 28 + 16 = 44 g/mol
Only NO has a molar mass of 30 g/mol.
✓Final answerThe answer is (b) NO — molar mass 30 g/mol matches the calculated value.
- CBSE 2018Set ANNUAL1 markQ.Write the ideal gas equation for one mole of a gas.
›Reveal solutionSolution
The general ideal gas equation PV = nRT reduces to PV = RT when n = 1 mole.
Step 1: The ideal gas equation combines Boyle's law (V proportional to 1/P at constant T,n), Charles's law (V proportional to T at constant P,n) and Avogadro's law (V proportional to n at constant P,T) into one relation: PV = nRT.
Step 2: Here P = pressure, V = volume, n = number of moles, R = universal gas constant (0.0821 L atm K^-1 mol^-1, or 8.314 J K^-1 mol^-1), T = absolute temperature (Kelvin).
Step 3: Substituting n = 1 mole gives the equation for one mole of an ideal gas: PV = RT.
✓Final answerPV = RT (for n = 1 mole).
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