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Solve · Q39

Q.A neon-dioxygen mixture contains 70.6 g dioxygen and 167.5g neon. If pressure of the mixture of the gases in the cylinder is 25 bar. What is the partial pressure of dioxygen and neon in the mixture?

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Step 1. Given 70.6 g O2 (M=32 g/mol) and 167.5 g Ne (M=20.18 g/mol), total pressure PTotal = 25 bar.

Step 2. Moles: n(O2) = 70.6/32 = 2.2063 mol; n(Ne) = 167.5/20.18 = 8.3003 mol; total moles = 2.2063 + 8.3003 = 10.5066 mol.

Step 3. Mole fractions: X(O2) = 2.2063/10.5066 = 0.2100; X(Ne) = 8.3003/10.5066 = 0.7900. …

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