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Q.At 25 degree C and 760 mm of Hg pressure a gas occupies 600 mL volume. What will be its pressure at the height where temperature is 10 degree C and volume of the gas 640 mL ?

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Step 1. Given: P1 = 760 mm Hg, T1 = 25 deg C = 298.15 K, V1 = 600 mL; find P2 at T2 = 10 deg C = 283.15 K, V2 = 640 mL (n constant throughout, so the combined gas law applies).

Step 2. From P1V1/T1 = P2V2/T2, solving for P2: P2 = (P1V1T2)/(T1V2) = (760 x 600 x 283.15)/(298.15 x 640). …

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