Skip to content
Miscellaneous Exercise 6 (II) · Q68

Q.Find the equations of the tangents to the circle x2+y2=16x^2+y^2=16 with slope −2-2.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
91% · 68/75 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

For x2+y2=16x^2+y^2=16 (r2=16r^2=16) with slope m=−2m=-2: c=±16(4)+16=±80=±45c=\pm\sqrt{16(4)+16}=\pm\sqrt{80}=\pm4\sqrt5. So the tangent lines are y=−2x±45y=-2x\pm4\sqrt5, i.e. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.