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Miscellaneous Exercise 6 (II) · Q53

Q.Find the equation of the locus of the point of intersection of perpendicular tangents drawn to the circle x=5cos⁡θx=5\cos\theta, y=5sin⁡θy=5\sin\theta.

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The circle x=5cos⁡θ, y=5sin⁡θx=5\cos\theta,\ y=5\sin\theta is x2+y2=25x^2+y^2=25 in Cartesian form (r=5r=5). The locus of the point of intersection of perpendicular tangents to a circle x2+y2=a2x^2+y^2=a^2 is its director circle, $x^2 …

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