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Miscellaneous Exercise 6 (II) · Q69

Q.Find the equations of the tangents to the circle x2+y2=4x^2+y^2=4 which are parallel to 3x+2y+1=03x+2y+1=0.

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Line 3x+2y+1=03x+2y+1=0 has slope m=−32m=-\dfrac32. For x2+y2=4x^2+y^2=4 (r2=4r^2=4): c=±4(94)+4=±9+4=±13c=\pm\sqrt{4\left(\frac94\right)+4}=\pm\sqrt{9+4}=\pm\sqrt{13}. So y=−32x±13y=-\dfrac32x\pm\sqrt{13}; multiplying by 22: $2y= …

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